周数据会有weekbegin和weekend两个字段,用来描述周的开始日期和结束日期. 现在项目中的日历控件不支持周查询,只支持日期查询,所以目前面临的问题是,根据时间范围,查询周. 最终sql如下: select uid,weekbegin,weekend,sum(activeCount),sum(newCount) from rv_Cloud_SummaryWeek where (date(weekbegin)>=date('2018-05-01') and date(weekbegin)<
oracle 查询最近执行过的 SQL语句 (2014-06-09 18:02:43) 转载▼ 分类: Database oracle 查询最近执行过的 SQL语句 select sql_text,last_load_time from v$sql order by last_load_time desc; SELECT sql_text, last_load_time FROM v$sql WHERE last_load_time IS NOT NULL and sql_text
查询分页的几种Sql写法 摘自:http://www.cnblogs.com/zcttxs/archive/2012/04/01/2429151.html 1.创建测试环境,(插入100万条数据大概耗时5分钟). create database DBTest use DBTest --创建测试表 create table pagetest ( id int identity(1,1) not null, col01 int null, col02 nvarchar(50) null, col03
SELECT TOP 10 TEXT AS 'SQL Statement' ,last_execution_time AS 'Last Execution Time' ,(total_logical_reads + total_physical_reads + total_logical_writes) / execution_count AS [Average IO] ,(total_worker_time / execution_count) / 1000000.0 AS [Average
查询数据库后台Block 的Sql存储过程 SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER OFF GO /*记录SQL Server的阻塞情况 wang 2008.8.11 (@P1 nvarchar(8),@P2 nvarchar(42),@P3 int,@P4 nvarchar(42),@P5 int,@P6 int,@P7 nvarchar(8),@P8 int) SELECT TOP 1 A.ITEMID,A.STATUSISSUE,A.INTER
oracle 查询最近执行过的 SQL语句 select sql_text,last_load_time from v$sql order by last_load_time desc; SELECT sql_text, last_load_time FROM v$sql WHERE last_load_time IS NOT NULL and sql_text like 'select%' ORDER BY last_load_time DESC; SELECT sql_tex
最近在网上找了下mysql查询随机的几个sql,我把最终的记录下来. SELECT * FROM uchome_mtag AS a JOIN (SELECT MAX(tagid) AS id FROM uchome_mtag) AS b ON (a.tagid>=FLOOR(b.id*RAND())) LIMIT 50 我试验后发现一个问题,当你的表里的总数和想要得到的条数很接近时,可能会不理想,有可能你有10条,你想查出随机的8条时,却只给出了5条的结果. 应该是那个大于等于造成的吧. 还有p
查询系统正在运行的SQL语句: select a.program, b.spid, c.sql_text from v$session a, v$process b, v$sqlarea c where a.paddr = b.addr and a.sql_hash_value = c.hash_value and a.username is not null;