阿尔茨海默症 (Alzheimer 's disease,AD) 是一种原发性的中枢神经系统退行性疾病.AD的主要临床症状是缓慢的认知功能减退,包括记忆.逻辑推理能力和语言功能的进行性丟失,最后发展为重度痴呆.目前,对AD尚缺乏早期诊断措施,当患者就诊时常常已经出现不可逆性脑损伤,导致治疗效果不佳.因此,发现早期高危因素对早期诊断和干预有重要意义.血小板与神经元在生物学上有诸多相似之处,因此,血小板是寻找中枢神经系统疾病外周生物标志物的理想基质. 近日,华中科技大学王建枝团队在衰老领域权威期刊A

Minieye杯第十五届华中科技大学程序设计邀请赛现场同步赛 I Matrix Again https://ac.nowcoder.com/acm/contest/700/I 时间限制:C/C++ 1秒,其他语言2秒 空间限制:C/C++ 262144K,其他语言524288K 64bit IO Format: %lld 题目描述 KK is the engineer responsible for sensor sensing in MINIEYE. KK recently need to u

(2015华中科技大学理科实验班选拔)已知三次方程$x^3+ax^2+bx+x=0$有三个实数根.(1)若三个实根为$x_1,x_2,x_3$,且$x_1\le x_2\le x_3,a,b$为常数,求$c$变化时$x_3-x_1$的取值范围.(2)若三个实数根为$a,b,c$,求$a,b,c$ 分析:$$\begin{cases} x_1+x_2+x_3&=-a\\ x_1x_2+x_2x_3+x_3x_1&=b\\ x_1x_2x_3&=-c\end{cases}$$为方便起见

链接:https://ac.nowcoder.com/acm/contest/560/D来源:牛客网 题目描述 Give you a rectangular gird which is h cells high and w cells wide. Each grid is black initially. You can turn some grids into white. A grid A(x,y) is connected with grid B if the coordinate of

题面见 https://ac.nowcoder.com/acm/contest/700#question 题目大意是有n个单词,有k条替换规则(单向替换),每个单词会有一个元音度(单词里元音的个数)和长度,现在希望利用替换规则(每个规则可使用无限次或不用)将每个单词替换成元音度值最小的单词,如果有多个单词元音度同等最小,那么取长度最小的单词.最后输出替换后的n个单词的元音度值之和与长度之和. 单纯每个点暴力搜,无疑会有爆复杂度的风险 1e5*1e5 ,如果记录搜过的点之后不搜,也会有在一个强连通

链接:https://pan.baidu.com/s/12gSzPHEgSNbT5Dl2QqDNpA 提取码:fw39 复制这段内容后打开百度网盘手机App,操作更方便哦 D    Grid #include <cstdio> #include <cstdlib> #include <cmath> #include <cstring> #include <string> #include <algorithm> #include &l

deb http://mirrors.hust.edu.cn/ubuntu/ trusty main restricteddeb-src http://mirrors.hust.edu.cn/ubuntu/ trusty main restricted deb http://mirrors.hust.edu.cn/ubuntu/ trusty-updates main restricteddeb-src http://mirrors.hust.edu.cn/ubuntu/ trusty-upda

第一步:下载锐捷客户端linux版本,下载网址为http://ncc.hust.edu.cn/cyxz/rzkhd.htm 第二步:解压该包,进入目录 #unzip RG_Supplicant_For_Linux_V1..zip #cd dir dir 是解压缩后的目录 第三步:输入命令 #chmod +x rjsupplicant.sh(赋予文件执行权限)#./rjsupplicant.sh -u 学号 -p 密码 -n 网卡 -s 服务类型 -d 1 -d代表使用dhcp方式动态分配ip地址

A - Beauty of Trees 题意: 链接:https://www.nowcoder.com/acm/contest/119/A来源:牛客网 Beauty of Trees 时间限制:C/C++ 2秒,其他语言4秒 空间限制:C/C++ 131072K,其他语言262144K 64bit IO Format: %lld 题目描述 It’s universally acknowledged that there’re innumerable trees in the campus of

链接:https://www.nowcoder.com/acm/contest/119/F来源:牛客网 Beautiful Land 时间限制:C/C++ 1秒,其他语言2秒 空间限制:C/C++ 131072K,其他语言262144K 64bit IO Format: %lld 题目描述 It’s universally acknowledged that there’re innumerable trees in the campus of HUST. Now HUST got a big

链接:https://www.nowcoder.com/acm/contest/106/K 来源:牛客网 题目描述 It's universally acknowledged that there're innumerable trees in the campus of HUST. Now you're going to walk through a large forest. There is a path consisting of N stones winding its way to

链接:https://www.nowcoder.com/acm/contest/106/J 来源:牛客网 题目描述 It's universally acknowledged that there're innumerable trees in the campus of HUST. And there are many different types of trees in HUST, each of which has a number represent its type. The doc

题目描述 It's universally acknowledged that there're innumerable trees in the campus of HUST. Thus a professional tree manager is needed. Your task is to write a program to help manage the trees. Initially, there are n forests and for the i-th forest the

链接:https://www.nowcoder.com/acm/contest/106/B 来源:牛客网 题目描述 It's universally acknowledged that there're innumerable trees in the campus of HUST. One day Xiao Ming is walking on a straight road and sees many trees line up in the right side. Heights of e

It’s universally acknowledged that there’re innumerable trees in the campus of HUST.Now HUST got a big land whose capacity is C to plant trees. We have n trees which could be plant in it. Each of the trees makes HUST beautiful which determined by the

题目1205:N阶楼梯上楼问题 时间限制:1 秒 内存限制:128 兆 特殊判题:否 提交:2447 解决:927 题目描写叙述: N阶楼梯上楼问题:一次能够走两阶或一阶,问有多少种上楼方式. (要求採用非递归) 输入: 输入包含一个整数N,(1<=N<90). 输出: 可能有多组測试数据.对于每组数据, 输出当楼梯阶数是N时的上楼方式个数. 例子输入: 4 例子输出: 5 import java.util.Scanner; public class Main{ static long F[]

呼,距离拿到华科cs的offer也有一段时间,有好几次准备动手写这篇经验帖,但就是理不清自己想表达什么,今早起来状态还不错,洗漱的时候思路居然通透了,哈哈哈~ 一.基本情况 先简单介绍笔者的一些基本情况吧,本人本科就读于江西师范大学,专业成绩还行(前五个学期是第二,最后的没去算了),大学三年主要的经历是一些竞赛(ACM-ICPC,CCPC,ICM,蓝桥杯,天梯赛)和学生工作(当过班长学生会副主席啥的),竞赛的奖项有是有一些,但没有特别拿得出手的(也算是本科的一个遗憾吧),英语的话大二上536过了

链接:https://www.nowcoder.com/acm/contest/106/K来源:牛客网 题目描述 It’s universally acknowledged that there’re innumerable trees in the campus of HUST. Now you're going to walk through a large forest. There is a path consisting of N stones winding its way to t

链接:https://www.nowcoder.com/acm/contest/106/J来源:牛客网 时间限制:C/C++ 1秒,其他语言2秒 空间限制:C/C++ 32768K,其他语言65536K 64bit IO Format: %lld 题目描述 It’s universally acknowledged that there’re innumerable trees in the campus of HUST. And there are many different types o

本文转载来自,华中科技大学江南雨烟的C/C++专栏部分STL剖析文章,以作学习之用. [1]  [C++ STL学习之一]容器的共通能力和共通操作总结 [2]  [C++ STL学习之二]容器vector大总结 [3]  [C++ STL学习之三]容器deque深入学习 [4]  [C++ STL学习之四]容器list深入学习 [5][C++ STL学习之五]容器set和multiset [6]  [C++ STL学习之六]STL算法之for_each [7]  [C++ STL学习之七]STL