problem description: there is four number list named A,B,C,D; now you should out put the num of tuples which statisfy A[i] +B[j]+C[k]+D[l] =0 i.e: Input: A = [ 1, 2] B = [-2,-1] C = [-1, 2] D = [ 0, 2] Output: 2 Explanation: The two tuples are: 1. (
#for 和 while #for用来迭代处理,什么叫迭代?你就当没看到这个词,for是把一堆玩意做一个一个加工用的,比如吃一袋花生,得一个一个剥吧,就是这意思 a = 'abcde' #每个字母当做一个花生,a是一袋子 for i in a: #从袋子里面一个一个拿花生,拿出的每一个花生都起名叫小i君 i = i + 'man' #把每个小i君都加个男人,停!加个说明,python里面不只是数值,好多玩意都能加减乘除,比如'a' + 'b',结果是'ab',前提是用来运算的元素要一样类型 p
[Python练习题 020] 求1+2!+3!+...+20!的和 -------------------------------------------------- 据说这题是"累积累加"的问题,把"1+2!+3!+...+20!"展开就变成: 1 1*2 1*2*3 1*2*3*4 -- 1*2*3*4--*20 弄懂了这规律,问题就好解决了.代码如下: sum = 0 x = 1 for i in range(1,21): x = x * i sum =
本题来自 Project Euler 第17题:https://projecteuler.net/problem=17 ''' Project Euler 17: Number letter counts If the numbers 1 to 5 are written out in words: one, two, three, four, five, then there are 3 + 3 + 5 + 4 + 4 = 19 letters used in total. If all th
在这个问题中,我们期望得到的结果是找到这三轮比赛中,每轮都进球的球员都有谁.下面用python来模拟一下,先生成一批数据: >>> from random import randint, sample >>> # sample是取样的意思,例如sample('abcde', 2),会在'abcde'这个字符串中随机抽样2个字符出来 >>> {x: randint(1,3) for x in sample('abcdef', randint(3, 6))