答:解1: select top 10 * from A where id not in (select top 30 id from A) 解2: select top 10 * from A where id > (select max(id) from (select top 30 id from A )as A) 首先就拿解1来select top 10 * from A表示取出前十条的数据 select top 30 id from A表示取出前30条的数据 现是取出大于30条的数
select top 10 * from (select ROW_NUMBER() over(order by Id) as rows,* from Customer) as C where C.rows>30 order by Id select top 10 * from Customer where id not in(select top 30 Id from Customer order by Id)order by Id select top 10 * from Customer w
现在有一个长度20的SET,其中每个对象的内容是随机生成的字符串,请写出遍历删除LIST里面字符串含"2"的对象的代码. public class RemoveTwo { //length用户要求产生字符串的长度 public static String getRS(int length){ String str="abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"; Random rand
题目如下: 子线程循环10次,接着主线程循环100,接着又回到子线程循环10次, 接着再回到主线程又循环100,如此循环50次 思路如下: 子线程语主线程为互斥,可用SYNCHRONIZED.很容易想到如下代码 package concurrent; public class theFirstIdea{ /** * @param args */ public static void main(String[] args) { new Thread(//子线程 new Runnable(){ pu
