公式法:两个数相乘等于最小公倍数乘以最大公约数 #define _CRT_SECURE_NO_WARNINGS #include <stdio.h> #include <stdlib.h> int gcd2(int a, int b) { int mod = a%b; ) { a = b; b = mod; mod = a%b; } return b; } int main() { int a, b; int cd; scanf("%d", &a); s
http://poj.org/problem?id=1348 Computing Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 1681 Accepted: 248 Description Input any five positive integral numbers n1, n2, n3, n4, n5, such that 0<=ni<=100, 1<=i<=5. To the first fou
Hey! Hope you had a great day so far! 今天想和大家讨论的是一道我从这学期cs的期末考试得到灵感的题:Get 24 Poker Game.说到 Get 24 Poker Game,也就是我们通常说的凑24点,大家可能都比较熟悉.但是因为这个游戏有很多变种,我们还是来简单说一下游戏的规则.老规矩,上Wikipedia: The 24 Game is an arithmetical card game in which the objective is to fi
题目链接 https://leetcode.com/problems/4sum/?tab=Description 找到数组中满足 a+b+c+d=0的所有组合,要求不重复. Basic idea is using subfunctions for 3sum and 2sum, and keeping throwing all impossible cases. O(n^3) time complexity, O(1) extra space complexity. 首先进行判断,由于是四个数相加
刷题备忘录,for bug-free leetcode 396. Rotate Function 题意: Given an array of integers A and let n to be its length. Assume Bk to be an array obtained by rotating the array A k positions clock-wise, we define a "rotation function" F on A as follow: F(k
1.找出所有的水仙花数: 水仙花数例如:153 的特点: 1^3+5^3+3^=153 而且水仙花数只会是三位数,所以可以利用循环的方式来解决问题,循环条件可以设为: var i = 1;i <=999; i++;因此具体过程如下: var a, b, c; 作用:接受水仙花数的百,十,个位数 for (var i = 100;i <=999; i++){ a = parseInt(i / 100); i百位上的数 b = parseInt(((i / 10) % 10)); i十位上
