在SQL SERVER中获取表中的第二条数据, 思路:先根据时间逆排序取出前2条数据作为一个临时表,再按顺时排序在临时表中取出第一条数据 sql语句如下: select top 1 * from(select top 2 * from NumberLog where UserName = '管理员' order by dateTime desc ) [table] order by dateTime asc
DECLARE @days INT, @date_start DATETIME = '2016-11-01', @date_end DATETIME = '2016-11-10' SET @days = DATEDIFF(DAY, @DATE_START, @DATE_END); SELECT DAY(DATEADD(dd, number, @DATE_START)) AS 日期 FROM master.dbo.spt_values WHERE type = 'p' AND number <=
例如查询 2012-1-5 到 2012-11-3 之间所有的月份 declare @begin datetime,@end datetime set @begin='2012-1-5' set @end='2012-11-3' declare @months int set @months=DATEDIFF(month,@begin,@end) select convert(varchar(7),DATEADD(month,number,@begin) ,120) AS 月份 from mas
直接贴代码了: 用户表: SELECT s.Name,Convert(varchar(max),tbp.value) as Description FROM sysobjects s AND (tbp.Name='MS_Description' OR tbp.Name is null) WHERE s.xtype IN('U') 示例: 用户视图: SELECT s.Name,Convert(varchar(max),tbp.value) as Description FROM sysobjec
直接贴代码了: SELECT sysobjects.name AS TableName, syscolumns.Id AS TableId, syscolumns.name AS DbColumnName, systypes.name AS DataType, syscolumns.length AS [Length], sys.extended_properties.[value] AS [ColumnDescription], syscomments.text AS DefaultValue