--方法1: with tmp as ( select '按时的撒旦123元(其中含存款11元)' name from dual union all select '一类似的预存9600元(新势力)' from dual ) select name,trim(translate( substr(name,,instr(name,'元')), translate( substr(name,,instr(name,'元')), ', ' '),' ' ) ) num from tmp; --方法2:
delphi 简单的删除字符串尾部数字的代码 方式一: function FilterShowName(const sName: String): String; var I: Integer; begin Result := sName; if Result <> '' then begin do begin ', '-'] then Delete(Result, I, ) else Break; end; end; end; 方式二(未测试): function GetChinese(S
写出将字符串中的数字转换为整型的方法,如:"as31d2v"->312,并写出相应的单元测试,输入超过int范围时提示不合法输入. public struct ConvertResult { public ConvertState State; public int Number; } public enum ConvertState { // 输入不合法 InValid = , // 输入合法 Valid = } public class StringHelper { publ
不说废话,贴代码: CREATE OR REPLACE FUNCTION to_time(sec IN NUMBER) RETURN VARCHAR2 IS /*把秒转成时分秒格式 auth lzpong 201/09/16 */ BEGIN ))), ,); EXCEPTION WHEN OTHERS THEN RETURN '0:00:00'; END to_time; CREATE OR REPLACE FUNCTION isnumeric(str IN VARCHAR2) RETURN