本文讲述了如何在OrCAD原理图中根据元件位号或者元件值快速查找元件的两种方法. 方法一:在.obj页面的“File”标签下查找元件. 方法二:在.obj页面的“Hierarchy”标签下查找元件. 工具/原料   PC Cadence OrCAD Capture软件 方法一:在.obj页面的“File”标签下查找元件   1 打开OrCAD原理图文件:菜单Flie → Open →Design... 或者直接点击工具栏上的“Open document”图标. 2 这时默认打开的是原理图的.ob

http://www.stmcu.org/module/forum/thread-600249-1-1.html 本人也是接触stm32没多久,之前用的MDK是5.1,现在用的是5.13,MDK5.0之前的版本(本人简称旧版)和之后的版本(本人简称新版)新建工程有很大区别.对于刚开始用学stm32的新手来说,基本上stm32 的视频教程,都是使用的旧版MDK,如果新手直接安装的是新版的MDK的话,往往总是会有一些困惑.     本人深有作为新手刚入手MDK5.13时新建工程的困惑感受,特地发了该

有时候在自定义navigationBar的左右按钮的时候,button的图片会显得很大,个人感觉原因有以下几种情况: 1.使用的是UIButton直接加在navigationBar上面 2.自定义了一个UIView,顶替系统的NavigationBar,button的frame值设置有问题. 如果是第一种情况解决方法如下: //左边城市选择 UIButton *LButton =[UIButton buttonWithType:UIButtonTypeCustom]; LButton.frame

本人也是接触stm32没多久,之前用的MDK是5.1,现在用的是5.13,MDK5.0之前的版本(本人简称旧版)和之后的版本(本人简称新版)新建工程有很大区别.对于刚开始用学stm32的新手来说,基本上stm32 的视频教程,都是使用的旧版MDK,如果新手直接安装的是新版的MDK的话,往往总是会有一些困惑.     本人深有作为新手刚入手MDK5.13时新建工程的困惑感受,特地发了该贴,以图文并茂的方式,详述了MDK5.13新建工程的步骤,只希望大家一起分享.学习,若有不足之处,望各位大大指正,

二叉树(Binary Tree)是最简单的树形数据结构,然而却十分精妙.其衍生出各种算法,以致于占据了数据结构的半壁江山.STL中大名顶顶的关联容器--集合(set).映射(map)便是使用二叉树实现.由于篇幅有限,此处仅作一般介绍(如果想要完全了解二叉树以及其衍生出的各种算法,恐怕要写8~10篇). 1)二叉树(Binary Tree) 顾名思义,就是一个节点分出两个节点,称其为左右子节点:每个子节点又可以分出两个子节点,这样递归分叉,其形状很像一颗倒着的树.二叉树限制了每个节点最多有两个子节

Given an array of numbers, verify whether it is the correct preorder traversal sequence of a binary search tree. You may assume each number in the sequence is unique. Follow up: Could you do it using only constant space complexity? 这道题让给了我们一个一维数组,让我们

Given a binary tree, determine if it is a valid binary search tree (BST). Assume a BST is defined as follows: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys

Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. 这道是之前那道Search in Rotated Sorted Array 在旋转有序数组

Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplic

Binary Tree: 0到2个子节点; Binary Search Tree: 所有左边的子节点 < node自身 < 所有右边的子节点: 1. Full类型: 除最下面一层外, 每一层都有两个子节点: 2. Complete类型: 除最下面一层外为Full类型, 但是最下面一层最所有子节点靠左: 3. Balanced类型: 左右两个子树的长度相差小于等于一: /** * Definition of TreeNode: * public class TreeNode { * public

Given a non-empty binary search tree and a target value, find the value in the BST that is closest to the target. Note: Given target value is a floating point. You are guaranteed to have only one unique value in the BST that is closest to the target.

Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST. According to the definition of LCA on Wikipedia: "The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has

随笔之——各大热门网站search 搜索框的写法,浅析!   关于搜索框,写法有很多种,搜索框这一块是一个比较细的活,要先计算好他的高.宽: 下面我就以京东搜索框为例,给大家浅析一下. 上面就是最终search框效果图. 先送出代码>>>>>> 1 <span style="color: #ff00ff; font-size: 18pt;"><strong>HTML 标签:</strong></span>

Verify Preorder Sequence in Binary Search Tree \Given an array of numbers, verify whether it is the correct preorder traversal sequence of a binary search tree. You may assume each number in the sequence is unique. Follow up: Could you do it using on

Unique Binary Search Trees Given n, how many structurally unique BST's (binary search trees) that store values 1...n? For example,Given n = 3, there are a total of 5 unique BST's. 1 3 3 2 1 \ / / / \ \ 3 2 1 1 3 2 / / \ \ 2 1 2 3   推导出递推公式即可: 对于1个元素来

Unique Binary Search Trees II Given n, generate all structurally unique BST's (binary search trees) that store values 1...n. For example,Given n = 3, your program should return all 5 unique BST's shown below. 1 3 3 2 1 \ / / / \ \ 3 2 1 1 3 2 / / \ \

Search in Rotated Sorted Array Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise retu

Given a binary tree, determine if it is a valid binary search tree (BST). Assume a BST is defined as follows: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys

Unique Binary Search Trees II Given n, generate all structurally unique BST's (binary search trees) that store values 1...n. For example, Given n = 3, your program should return all 5 unique BST's shown below. 1         3     3      2      1 \      

二叉查找树(Binary Search Tree),也称二叉排序树(binary sorted tree),是指一棵空树或者具有下列性质的二叉树: 若任意节点的左子树不空,则左子树上所有结点的值均小于它的根结点的值 任意节点的右子树不空,则右子树上所有结点的值均大于它的根结点的值 任意节点的左.右子树也分别为二叉查找树 没有键值相等的节点(no duplicate nodes) 本文地址:http://www.cnblogs.com/archimedes/p/binary-search-tree

LeetCode:Unique Binary Search Trees Given n, how many structurally unique BST's (binary search trees) that store values 1...n? For example,Given n = 3, there are a total of 5 unique BST's. 1 3 3 2 1 \ / / / \ \ 3 2 1 1 3 2 / / \ \ 2 1 2 3 分析:依次把每个节点作