问题描述:求商,不能用乘法,除法,取模运算. 算法思路:不能用除法,那只能用减法,但是用减法,超时.可以用位移运算,每次除数左移,相当于2倍. public class DividTwoIntegers { public int divide(int dividend, int divisor) { if(divisor == 0) return Integer.MAX_VALUE; if(divisor == -1 && dividend == Integer.MIN_VALUE) re
Equations are given in the format A / B = k, where A and B are variables represented as strings, and k is a real number (floating point number). Given some queries, return the answers. If the answer does not exist, return -1.0. Example:Given a / b =
https://stackoverflow.com/questions/36662920/xcode-clang-link-build-dynamic-framework-or-dylib-not-embed-dependencies clang use ld command to make the final link, I checked the manual and found -U and -undefinedcan ignore undefined symbols. -U symbol
对于操作数的左位移都是相同的,右边空出来的位置用0补齐. 但是对于右位移,对于有符号和无符号数是不一样的,最高位的1有两种处理方式.逻辑位移和算术位移. 逻辑位移:右移入位用0补齐 算术位移:右移入位用原先的该值得符号位决定. #include <stdio.h> int main() { int num = -128; printf("%08x\n",num); num = num >> 4; printf("%08x\n",num); n