http://stackoverflow.com/questions/24069197/httpresponse-object-json-object-must-be-str-not-bytes HTTPResponse object — JSON object must be str, not 'bytes' up vote17down votefavorite 7 I've been trying to update a small Python library called libpyne
File "C:\Python27\lib\json\__init__.py", line 290, in load **kw) File "C:\Python27\lib\json\__init__.py", line 351, in loads return cls(encoding=encoding, **kw).decode(s) File "C:\Python27\lib\json\decoder.py", line 365, in d
How do I add new attribute (element) to JSON object using JavaScript? JSON stands for JavaScript Object Notation. A JSON object is really a string that has yet to be turned into the object it represents. To add a property to an existing object in JS
利用python中的json读取json文件时,因为错误使用了相应的方法导致报错:TypeError:the Json object must be str, bytes or bytearray,not‘TextIOWrapper’. 解决方法: 首先要弄明白json有四个方法:dumps和loads.dump和load.其中,dumps和loads是在内存中转换(python对象和json字符串之间的转换),而dump和load则是对应于文件的处理. 出现这个错误的原因是自己用了loads方
{ "ErrorDump": "the JSON object must be str, not 'bytes'", "StatusCode": "500" } response = clt.do_action_with_exception(request___) ## { "ErrorDump": "the JSON object must be str, not 'bytes'",
Adding property to a json object in C# you can do it with a dynamic object dynamic obj = JsonConvert.DeserializeObject<ExpandoObject>(jsonString); obj.Values.valueName4 = "value4"; System.Console.WriteLine(JsonConvert.SerializeObject(obj
第一次遇到这样的异常,实在不知道如何是好?进行了测试发现报错的json出没有问题,而且每次出现异常的位置不一样 于是我认为这样的问题可能是因为程序执行过快,所以很简单的解决办法是: def deal_dealers_info(self): province_list = self.get_province_list() for province in province_list: if province== None:
//将表单序列化成字符串 $.fn.serializeObject = function () { var obj = {}; var count = 0; $.each(this.serializeArray(), function (i, o) { var n = o.name, v = o.value; count++; obj[n] = obj[n] === undefined ? v : $.isArray(obj[n]) ? obj[n].concat(v) : [obj[n], v
web 开发的过程中我们经常需要返回对象的json 格式,使用node express 是比较简单的, 1.node express 基础网站的创建 比较简单,以前的文章有 2.编写对象并导出对象 /*** Created by Dalong on 14-1-21. */function User(username,userage){ this.username=username; this.userage=userage;}User.prototype.say=functio