using ( androidhiveEntities db = new androidhiveEntities() ) { #region 添加 //aa a = new aa() { endDate =DateTime.Now,name="张三",doccode="ddoccode ",startDate=DateTime.Now };
今天机缘巧合,无意听到别人闲聊,突发奇想设计一套系统来解决他们的痛点,待我进一步分析下如何执行.回到主题,最近修改ID的工作做了不少.企业补充历史数据用.现总结如下: 1.想把递增ID某一段的ID都加上10,本以为写一条UPDATE 语句 如下 SET IDENTITY_INSERT c1 ON UPDATE c1 SET ID=ID+10 WHERE ID<15 AND ID>10 SET IDENTITY_INSERT c1 OFF 结果执
案例分析: 现在要查询一个表单里面的运费结果,但是他还有分录,为了显示分录,必须把表头显示出来,问题是,他要查询运费的合计, 但是这样就会导致重复行也加进去了,这样显然数据不准,为此,可以把重复的行设置为0. 方法: row_number()over(partition by 字段 order by 字段)ID 相当于把一个字段来分组,然后对于这个字段而言,相当于单独字段ID,分别设置值为1,2,3,4,5,排序,有点类似rownum,我们可以把ID字段不等于1的设置为0,这样就不会 重复了.
http://www.cnblogs.com/zfz15011/archive/2010/05/30/1747486.html 1.传统修改模式,看下列代码 using (NorthwindEntities context = new NorthwindEntities()){ Region region = context.Region.FirstOrDefault(v => v.RegionID == 4); region.RegionDescription = "Test
调试发现,查询到的就是一条数据 hql语句执行结果 Hibernate: select ballmodel0_.ball_id as ball_id1_1_, ballmodel0_.color as color2_1_, ballmodel0_.origion as origion3_1_, ballmodel0_.owner as owner4_1_, ballmodel0_.province as province5_1_ from t_ball ballmodel0_ 但是另一个dao的
#!/bin/bash IFS=$'\n' #conf start commid id startCommitId=030cd2bf4e3694fe3a3b6f069556c4ea91a9858d lastCommitId="123" for log in $(git log --pretty=oneline) do commitId=${log:0:40} desc=${log:41} #echo "commitId:${commitId} desc:${desc}&quo