function getUrlRequestParam(name) { var paramUrl = window.location.search.substr(1); var paramStrs = paramUrl.split('&'); var params = {}; for (var index = 0; index < paramStrs.length; index++) { params[paramStrs[index].split('=')[0]] = decodeURI(p
HttpServletRequest 获取请求的URL的方法有: 1.request.getRequestURL() 返回的是完整的url,包括Http协议,端口号,servlet名字和映射路径,但它不包含请求参数.2.request.getRequestURI() 得到的是request URL的部分值,并且web容器没有decode过的 3.request.getContextPath() 返回 the context of the request. 4.request.getServlet