匹配时间: # -*- coding:utf-8 -*- import re def parseDate(l): patternForTime = r'(\d{4}[\D]\d{1,2}[\D]\d{1,2}[\D]?)' for i in l: m = re.search(patternForTime, i) if m: print(m.group(1)) if __name__ == '__main__': l = ['永康市雅致医疗器械有限公司', '郑云燕', 'II类:6863-16-
java 正则匹配空格字符串 正则表达式截取字符串 需求:从一堆sql中取出某些特定字符串: 比如配置的sql语句为:"company_code = @cc and project_id = @pid ; update t set a = @aa,b=@bb,c=@cd,ttt=@ttt;update t2 set d=@bb"; 我要拿出所有的以@开头的作为变量,并且去重,则如下玩: ps:其中正则匹配空格是 “\s+” public class Test { public stat
本文始发于个人公众号:TechFlow 这是LeetCode的第10题,题目关于字符串的正则匹配,我们先来看题目相关信息: Link Regular Expression Matching Difficulty Hard Description Given an input string (s) and a pattern (p), implement regular expression matching with support for '.' and '*'. '.' Matches an