find the longest of the shortest Time Limit: 1000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2524 Accepted Submission(s): 888 Problem Description Marica is very angry with Mirko because he found a new gi
//随便创建一个数组 let data = "abcdefghijklmnopkrstuvw12322999".split(""); //总数组 let productData=[]; //分数组 let falseData = []; //小下标 let index = 0; //如果是数组并且长度大于零 if(Array.isArray(data)&&data.length>0){ //循环原一维数组 for (let i = 0; i &
var keyMap = { deviceUid: "id", deviceType: "typeName", deviceCode: "code", deviceName: "name", deviceStatus: "status" }; for (var i = 0; i < data.confList.length; i++) { var obj = data.confList[i]; for
删除表中重复记录,只保留一条: delete from 表名 where 字段ID in (select * from (select max(字段ID) from 表名 group by 重复的字段 having count(重复的字段) > 1) as b); 实例: 2.当想要为某一个表建立一个唯一索引,由于表中有重复记录而无法进行时,需要删除重复记录. 例表 dept id_no id_name 100 'AAA' 101 'BBB' 102 'CCC' 103 'DDD' 100 'E
用SQL语句,删除掉重复项只保留一条 在几千条记录里,存在着些相同的记录,如何能用SQL语句,删除掉重复的呢 1.查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断 select * from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1) 2.删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有
在网上看过一些解决方法 我在此给出的方法适用于无唯一ID的情形 表:TB_MACVideoAndPicture 字段只有2个:mac,content mac作为ID,正常情况下mac数据是唯一的,由于操作失误导致数据插入多次,导致出现多个mac,content重复数据,现在只保留一条,删除多余的 大体思想是给重复数据一个自增ID,过滤出每组里面最小ID,删除原数据中所有重复数据再将最小ID插入 --查询出所有重复数据,并给定递增id , ) AS id , mac , content INTO