var num = new Array(10000).fill('').map((item,index) => (index + 1)). 在点号后面补充代码,让num是这个数组中0出现的次数,100算出现了2次0 var num = new Array(10000).fill('').map((item,index) => (index + 1)).reduce((pre,current) => { return pre + (function(current) { // 方法一 //
/****************************************************************** find the biggest x number in a sequence* the basic method is the same as the QuickSort** 1. move the smaller one before the pivot* 2. move the bigger one after the pivot* 3. determin
如何快速查找一个字符串中出现最多的字符,并统计出现的次数? 可以使用hash数组,也就是关联数组实现快速查找功能. function seek(str) { var hash = []; var max=-1; var max_key=''; for(var i=0,l=str.length;i<l;i++){ var key=str[i]; if(!hash[key]){ hash[key]=1; }else{ hash[key]++; } } //console.dir(hash); //遍
JS如何从一个数组中随机取出一个元素或者几个元素. 假如数组为 var items = ['1','2','4','5','6','7','8','9','10']; 1.从数组items中随机取出一个元素 //code from http://caibaojian.com/js-get-random-elements-from-array.html var item = items[Math.floor(Math.random()*items.length)]; 2.从前面的一篇随机数组中随机
题目:找出一个数组中第m小的值并输出. 代码: #include <stdio.h> int findm_min(int a[], int n, int m) //n代表数组长度,m代表找出第m小的数据 { int left, right, privot, temp; int i, j; left = 0; right = n - 1; while(left < right) { privot = a[m-1]; i = left; j = right; do { while(privo
题目: Given two sorted integer arrays A and B, merge B into A as one sorted array. Note: You may assume that A has enough space to hold additional elements from B. The number of elements initialized in A and B are m and n respectively. 题意要把两个有序的数组合并到他们
# -*- coding: utf-8 -*- #使用迭代查找一个list中最小和最大值,并返回一个tuple #遍历list,找到最小值 def findMinAndMax(L): if L==[]: return(None, None) else: a=L[0] b=L[0] for num in L: if num<a: a=num for num in L: if num>b: b=num return (a,b) print(findMinAndMax([1,2,3,4,5,6]))
