今天在review项目代码的时候看到这样一个问题,有一张号码表,每次需要从这样表中随机取6个空闲的号码,也就是每次取出来的6个号码应该都会有所不同.然后我就看到了这样的SQL select t.* from tel_number_tbl t where t.status = '空闲' and t.area_code = '0571' and t.delete_flg = '未删除' and rownum <= 6order by
我想把数组打乱随机取些值,于是用PHP的shuffl()打乱数组,当然,array_rand()也是可以随机取数组的,但是我想到另一个更高效的办法,是不是能用sql直接随机数据?当然可以! mysql是这样实现的: select * from tablename order by rand() limit 10 说明:rand()返回在范围0到1.0内的随机浮点值 sqlserver是这样实现的: select top 10 * from tableName order by NewID() 说
Given an array w of positive integers, where w[i] describes the weight of index i, write a function pickIndex which randomly picks an index in proportion to its weight. Note: 1 <= w.length <= 10000 1 <= w[i] <= 10^5 pickIndex will be called at
随机取3条不重复的记录 [Access]select top 3 * from tablename order by rnd(id); [SqlServer]select top 3 * from tablename order by newid(); [MySQL]select * from tablename order by rand() limit 0,3; [Oracle]select * from (select * from tablename order by dbms_rand
oracle 中随机取一条记录的两种方法 V_COUNT INT:=0; V_NUM INT :=0; 1:TBL_MYTABLE 表中要有一个值连续且唯一的列FID BEGIN SELECT COUNT(*) INTO V_COUNT FROM TBL_MYTABLE; SELECT TRUNC(DBMS_RADOM.VALUE(1,V_COUNT+1)) INTO V_NUM FROM DUAL; SELECT * FROM TBL_MYTABLE T WHERE T.FID=V_NUM;