javaScript获取url问号后面的参数方法 function GetRequest() { var url = location.search; //获取url中"?"符后的字串 var theRequest = new Object(); if (url.indexOf("?") != -1) { var str = url.substr(1); strs = str.split("&"); for(var i = 0; i &l
实例代码test.js var http=require('http'); var url=require('url'); var querystring=require('querystring'); http.createServer(function(request, response) { var urlStr = request.url; var methodName = urlStr.substring(1, urlStr.indexOf('?')); console.log('me
一:后台获取,前台调用 后台: object value= Request.QueryString[key]; 前台js: $(function(){ var value="<%=value %>" }) 二:用js方法写正则判断 //获取URL中参数 function getUrlParam(name) { var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)&quo
原理跟取cookie值一样的 function getParamer(paramer){ var url=window.location.href.split("?")[1];/*获取url里"?"后面的值*/ if(url.indexOf("&")>0){/*判断是否是一个参数还是多个参数*/ urlParamArry=url.split("&");/*分开每个参数,并放到数组里*/
解决方法 function getQueryString(key){ var reg = new RegExp("(^|&)"+key+"=([^&]*)(&|$)"); var result = window.location.search.substr(1).match(reg); return result?decodeURIComponent(result[2]):null; } 下面的这种方法获取到url中的中文参数是乱码 /*fu
String.prototype.getQuery = function(name){ var reg = new RegExp("(^|&)"+ name +"=([^&]*)(&|$)"); var r = this.substr(this.indexOf("\?")+1).match(reg); if (r!=null) return unescape(r[2]); return null; }var s =
工具方法: function getRequest() { var url = location.search; // 获取url中?后面的字符串 var theRequest = new Object(); if (url.indexOf("?") != -1) { var str = url.substr(1); strs = str.split("&"); for (var i = 0; i < strs.length; i++) { theRe
function GetRequest() { var url = location.search; //获取url中"?"符后的字串 var theRequest = new Object(); if (url.indexOf("?") != -1) { var str = url.substr(1); strs = str.split("&"); for(var i = 0; i < strs.length; i ++) { t
function GetRequest() { var url = location.search; //获取url中"?"符后的字串 var theRequest = new Object(); if (url.indexOf("?") != -1) { var str = url.substr(1); strs = str.split("&"); for(var i = 0; i < strs.length; i ++) { t
function GetRequest() { var url = location.search; //获取url中"?"符后的字串 var theRequest = new Object(); if (url.indexOf("?") != -1) { var str = url.substr(1); strs = str.split("&"); for(var i =
写在前面的 没啥说的 上代码 思路就是先获取到?后面的参数区,然后 利用字符串转数组方法获取到各个参数 var json = {}; var url = 'https://www.baidu.com/index.html?a=12&b=asdf&c=&d'; url = url.replace(/.*\?/,''); var arr = url.split('&'); var temp; for (var i = 0;i < arr.length;i++) { tem
function getUrlParam(name) { var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)"); //构造一个含有目标参数的正则表达式对象 var r = window.location.search.substr(1).match(reg); //匹配目标参数 if (r != null) return unescape(r[2]); return null; //返回
function getAllUrlParams(url) { // get query string from url (optional) or window var queryString = url ? url.split('?')[1] : window.location.search.slice(1); // we'll store the parameters here var obj = {}; // if query string exists if (queryString)
<script type="text/javascript"> function GetQueryString(name) { var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)"); var r = window.location.search.substr(1).match(reg); if (r != null) return r[2]; return
function getUrlRequestParam(name) { var paramUrl = window.location.search.substr(1); var paramStrs = paramUrl.split('&'); var params = {}; for (var index = 0; index < paramStrs.length; index++) { params[paramStrs[index].split('=')[0]] = decodeURI(p