排序 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 75271 Accepted Submission(s): 23079 Problem Description 输入一行数字,如果我们把这行数字中的‘5’都看成空格,那么就得到一行用空格分割的若干非负整数(可能有些整数以‘0’开头,这些头部的‘0’应该被忽略掉,除非这个整数就是由
S and T are strings composed of lowercase letters. In S, no letter occurs more than once. S was sorted in some custom order previously. We want to permute the characters of T so that they match the order that S was sorted. More specifically, if x occ
原文http://bbs.csdn.net/topics/390594744?page=1#post-395599672 //排序数组 function SortBy(field, reverse, primer) { reverse = (reverse) ? -1 : 1; return function (a, b) { a = a[field]; b = b[field]; if (typeof (primer) != 'u