分组后,统计记录条数: SELECT num,count(*) AS counts from test_a GROUP BY num; 查询结果如下: 对num去重后的数量的统计: SELECT count(t.counts) FROM ( SELECT num,count(*) AS counts from test_a GROUP BY num ) AS t; SELECT count(DISTINCT num) AS count FROM test_a; 它俩结果一样,都是5:只是一个是子
百度经验 COUNT(CASE WHEN (S.rank = 1) THEN S.loanContractId END ) AS 'MZ', //根据loanContractId 分组,并统计rank=1出现的次数 CI 框架 /** * 获取三种消息类型各自的未读数 * @param int $user_id 用户的id * */ public function get_unread_count($user_id) { $this->db->select('COUNT( CASE WHEN
Summer Holiday Time Limit: 10000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4574 Accepted Submission(s): 2078 Problem Description To see a World in a Grain of Sand And a Heaven in a Wild Flower, Hold Inf
as tjsl from fyxx group by zt,whbmbh end) as ybhsl from fyxx group by whbmbh 下面是摘自别人的博客 最近遇到一个问题,需要对一张表做统计,这个统计有什么特别之处值得我记录了下来呢?大家知道SQL中聚合函数GROUP BY的结果一般为一列,即多个值通过聚合函数运算统计到一起,但是如何将不同条件的值统计到不同列中呢,即按条件统计到多个列中.举个栗子: YEAR TYPE VALUE 2015 1 100 2015 2 200
1.使用case when方法(不建议使用)- 代码如下 复制代码 SELECT COUNT(DISTINCT user_id) user_count, CASE WHEN create_time>1395046800 AND create_time<1395050400 THEN '17:00-18:00' WHEN create_time>1395050400 AND create_time<1395054000 THEN '18:00-19:00'
select flow_id,rw from (select t.flow_id ,rownum as rw from apex_030200.wwv_flow_list_templates t) where rw >= 5 1.rownum只能用<如果使用>加别名 2.子查询引用只能在查询出的结果中引用,比如子查询没有查出flow_id,外层不能用,另外外层不能引用内层的t 3.薪水前三名,内层查出薪水 order desc的虚表外层使用rownum<3 4.merge可以实现
SELECT count(*) FROM 表名 WHERE 条件 // 这样查出来的是总记录条 SELECT count(*) FROM 表名 WHERE 条件 GROUP BY id //这样统计的会是每组的记录条数. 如何获得 第二个sql语句的总记录条数? 则是,如下: select count(*) from(SELECT count(*) FROM 表名 WHERE 条件 GROUP BY id ) a ; 注意: 子查询方式,MySQL中子结果集必须使用别名,而Oracle中不需要特
select whbmbh ,zt,1 as tjsl from fyxx group by zt,whbmbh select whbmbh,sum(case zt when '有效' then 1 end) as yxsl,sum(case zt when '暂缓' then 1 end )as zhsl,sum(case zt when '未知' then 1 end) as wzsl,sum(case zt when '我租' then 1 end) as wzsl,sum(case zt