在Oracle中实现select top N:由于Oracle不支持select top 语句,所以在Oracle中经常是用order by 跟rownum的组合来实现select top n的查询.简单地说,实现方法如下所示:select 列名1 ...列名n from(select 列名1 ...列名n from 表名 order by 列名1)where rownum <=N(抽出记录数)order by rownum asc 如:select id,name from (selec
不同的数据库,支持的SQL语法略有不同,以下是不同数据库查询前n条数据的SQl语句 SQL Server(MSSQL) SELECT TOP n * FROM table_name ORACLE SELECT * FROM table_name WHERE ROWNUM <= 10; MySQL SELECT * FROM table_name LIMIT 10;
sql在不同数据库查询前几条数据 1. ORACLE SELECT * FROM TABLE_NAME WHERE ROWNUM <= N; HQL: from table_name t order by t.create_time desc where rownum<=n; 2. postgres查询前几条记录SQL SELECT * FROM TABLE_NAME LIMIT N; 3. DB2 SELECT * ROW_NUMBER() OVER(ORDER BY COL1 DESC
左边是mongodb语句,右边是sql语句 db.users.find() select * from users db.users.find({"age" : 27}) select * from users where age = 27 db.users.find({"username" : "joe", "age" : 27}) select * from users where "username"
左边是mongodb查询语句,右边是sql语句.对照着用,挺方便. db.users.find() select * from users db.users.find({"age" : 27}) select * from users where age = 27 db.users.find({"username" : "joe", "age" : 27}) select * from users where "us