问题描述 版本:MySQL 5.7.24 SQL语句: SELECT wave_no, SUM(IF(picking_qty IS NULL, 0, picking_qty)) AS PICKED_QTY, SUM(IF(differ_qty IS NULL, 0, differ_qty)) AS PICKED_DIFFER_QTY, SUM(IF(relocate_qty IS NULL, 0, relocate_qty)) AS PICKED_RELOCATE_QTY FROM pickin
题目链接:http://poj.org/problem?id=1523 SPF:A Single Point of Failure也就是割点(一个点导致网络之间的不连通),由于给出的图是无向图,所以只要连通就一定强连通.要求连通分支的数量就是要求请联通分支的数量,我们可想到tarjan求强连通的步骤,只要一群结点的low值相同他们就是属于同一个SCC(Strongly Connected Component),所以我们只要对于每一个割点,记录一下这个点所到的其他结点的不相同的low值的数量,就是
1 使用原生SQL语句更新--Database.ExecuteSqlCommand 假设你有一张如图9-1所示的Payment数据库表. 图9-1 1.1 实体类型: public class Payment { public int PaymentId { get; set; } public decimal Amount { get; set; } public string Vendor { get; set; } } 1.2 数据访问类: public class EF6RecipesC