记录备忘下,初始数据如下: DROP TABLE IF EXISTS t_demo_product; CREATE TABLE IF NOT EXISTS t_demo_product( proid ), proname ), price ), PRIMARY KEY(proid) )ENGINE=InnoDB DEFAULT CHARSET=gbk; DROP TABLE IF EXISTS t_demo_operation; CREATE TABLE IF NOT EXISTS t_demo
内连接查询 内连接与SqL中inner join一样,即找出两个序列的交集 Model1Container model = new Model1Container(); //内连接 var query = from s in model.Student join c in model.Course on s.CourseCno equals c.Cno select new { ClassID = s.CourseCno, ClassName = c.Cname, Student = new {
.左连接: var LeftJoin = from emp in ListOfEmployees join dept in ListOfDepartment on emp.DeptID equals dept.ID into JoinedEmpDept from dept in JoinedEmpDept.DefaultIfEmpty() select new { EmployeeName = emp.Name, DepartmentName = dept != null ? dept.Name
SQL: 外连接和内连接: 左连接或左外连接:包含左边的表的所有行,如果右边表中的某行没有匹配,该行内容为空(NULL) --outer jion:left join or left outer join select * from dbo.Project left join dbo.Voice on (dbo.Project.voiceID=dbo.Voice.ID) 右连接或右外连接:包含右边表的所有行,如果左边表中的某行没有匹配,该行内容为空(NULL) --outer jion:righ
数据库中学生表和课程表如下: 内连接sql语句: select a.studentName,a.studentAge,b.courseName from student a inner join course b on a.studentID=b.studentID 查询结果如下: 查询的结果是以从表course为主,没有就不显示.
--表stuid name 1, Jack2, Tom3, Kity4, nono--表examid grade1, 562, 7611, 89 内连接 (显示两表id匹配的)select stu.id,exam.id,stu.name, exam.grade from stu inner join exam on stu.id=exam.idstu.id exam.id name grade--------------------------------1 1 Jack 562 2 Tom 7