转载自:http://blog.csdn.net/jie11447416/article/details/50887888 1.案例中的数据结构和数据如下 2.在没有解决的时候,是这样的 SELECT date(downtime) AS dday, count(*) AS num FROM re_device GROUP BY dday 得到如下结果,如果那天没有数据,那麽就会没有记录 我们看到,时间不连续,没有2016-3-05这一天的,这样本来不是问题,但是,我拿出来的数据,还要画出
delete from 表名 where id not in (select d.id from (SELECT id FROM 表名 GROUP BY c1,c2,c3,c4)as d) #去重复,把url重复,且区为空的中去掉.select * from TABLE where url in (select u.url from (select * from TABLE where id not in (select d.id from (SELECT id FROM TABLE GROUP
做个笔记 SQLyog客户端访问MySQL服务器 统计数据:次数总数, 次数成功率,对象(obj)总数,对象(obj)成功率 要求:按时间排序和分组 sql语句如下: SELECT a.date AS `日期`, a.total AS `总次数`, a.objs AS `总对象数`, , ) AS `失败次数比率`, , ) AS `对象失败率` FROM (SELECT ) AS `total`, COUNT(DISTINCT(`obj_id`)) AS `objs`, , NULL)) AS