一.JSON类型 答案是不可以 为Json类型建索引会报错 mysql)); ERROR (): JSON column 'card_pay_data' cannot be used in key specification. 二.text类型 答案是可以的,但是需要指定长度 mysql> CREATE INDEX idx2 ON user (tests); ERROR (): BLOB/TEXT column 'tests' used in key specification without
SELECT name, profile->"$.twitter" AS `twitter` FROM `user` WHERE profile->"$.twitter" IS NOT NULL; https://dev.mysql.com/doc/refman/5.7/en/json-search-functions.html https://www.sitepoint.com/use-json-data-fields-mysql-databases/
1.模糊搜索 第一时间我马上想到了关键字 like 1.1.所要查询的字段中包含特定 字符,但不确定其位置,使用两个%包起来 select * from phone where provider like '%Apple%' 可以匹配 'AppleXXX', 'xxAppleXX', 'ABCDefgApple' 1.2.能够确定要查字段的结尾,则如下: select * from Student where name like '%聪'; 可以匹配到 '黄聪', '聪
MySQL 5.7.8开始支持 json类型. create table t(id int,js json,PRIMARY KEY (`id`)) 插入数据insert into t values(1,'{"a":1,"s":"abc"}')insert into t values(2,'[1,2,{"a":123}]')insert into t values(3,'"str"')insert into