找第一层: SELECT * FROM tourists WHERE json_data->'$.weixinOpenId' = '299485886686868' 或者 SELECT * FROM devices WHERE JSON_EXTRACT(json_data, "$.lcswAccessToken") = '33e5028835bf4d478ed5cd8f8a618ea5' 找多层: SELECT * FROM devices WHERE json_extract(
1 GROUP_CONCAT mysql> SELECT student_name, -> GROUP_CONCAT(test_score) -> FROM student -> GROUP BY student_name; Or: mysql> SELECT student_name, -> GROUP_CONCAT(DISTINCT test_score -> ORDER BY test_score