问题:找出一个元素序列中出现次数最多的元素是什么 解决方案:collections模块中的Counter类正是为此类问题所设计的.它的一个非常方便的most_common()方法直接告诉你答案. # Determine the most common words in a list words = [ 'look', 'into', 'my', 'eyes', 'look', 'into', 'my', 'eyes', 'the', 'eyes', 'the', 'eyes', 'the', '
直接上代码 /** * Created by lvhao on 2017/6/30. * Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the arra
1.最小数 // 1.0 public class SortDemo1 { public static void main(String[] args) { int[] a = {2,5,4,6,8,1,3,9}; int min = a[0];//最小数 int k = 0; int temp; for(int i = 0; i < a.length; i++ ) { System.out.print( a[i] + "\t"); } //最小数 for(int j = 0;
一. 去重并保持原来元素的顺序 def dedupe(items): h = [] for item in items: if item not in h: h.append(item) return h #a = [, , , , , , , ] a = [ {, }, {, }, {, }, {, }] b = dedupe(a) print(b) 二. 命名切片 假定你有一段代码要从一个记录字符串中几个固定位置提取出特定的数据字段,用切片取出想要的字符 record = '........
