版权声明:本文为博主原创文章,未经博主同意不得转载. https://blog.csdn.net/u011925175/article/details/24186917 有一个mysql数据库的表,要查询他的最后两条数据的结果例如以下: 这是原表中的内容: idname 1 ad 2 jk 3 tre 4 hgv 这是查询的最后两条的数据的内容(为最新的插入的数据): 语句:select * from demo1 order by id desc limit 0,2; 结果:id n
摘要: 下文讲述使用sql脚本实现相邻两条数据相减的方法,如下所示: 实验环境:sql server 2008 R2 实现思路: 1.使用cte表达式,对当前表进行重新编号 2.使用左连接对 表达式 生成的临时表进行错位连接,并对生成的新纪录中两列进行相减 ),qty int); go ----生成基础数据 insert into [maomao365](sort, qty)values (),(), (),(), (),() go with cte_temp as ( select row_n
思路: 先将取出的值随机排序,然后在随机排序的每次取第一条的结果 举例如下: select * from(select t.code fromTBIZOPS_PROVINCE t ORDER BY DBMS_RANDOM.RANDOM())where rownum < 2;select * from (select t.code from TBIZOPS_CITY t wheret.province_id = '13' ORDER BY DBMS_RANDOM.RANDOM()) where
declare ) ) --获取表的列名 ,),filename INTO #templist FROM (select cl.name as filename from sys.tables AS tb,sys.columns cl where tb.object_id = cl.object_id and tb.name='book') AS A SELECT @intMinId =MIN(RowID),@intMaxId=MAX(RowID) FROM #templist --这里必须设置
<!-- 计算每两次消费的间隔天数 --> SELECT B.MEN_ID,TIMESTAMPDIFF(DAY,B.PRE_DATE,B.CURR_DATE) AS DAYS FROM ( <!-- 行变列 --> SELECT A.MEN_ID,A.ORDER_DATE AS CURR_DATE,@A.ORDER_DATE AS PRE_DATE,@A.ORDER_DATE:= A.ORDER_DATE FROM TBL_MAS_ORDER_MASTER A,(SELECT @A
update groupuser as g1 join groupuser as g2 on (g1.user_id=1 and g2.user_id = 2) or(g1.user_id = 2 and g2.user_id=1) set g1.group_id = g2.group_id,g2.group_id=g1.group_id;
begin ),(, ))) from workplan a join org_employee b on b.id = a.idowner , LEN(aa.sglzbbh))) glh from workplan aa group by aa.idowner ) c on c.id = a.idowner where a.id = '${targetID}' --自动关联上周计划编号 --自动关联上周计划编号 update a set a.idszzb = b.id from workpla
insert all into T_TRAIN_MARSHALLING <trim prefix="(GKEY," suffix=")" suffixOverrides=","><if test="ID != null and ID != '' ">ID,</if><if test="1 == 1">TRAIN_NUM,</if><if te
