以下三种方法均可实现周岁年龄的计算: --算法一: SELECT TRUNC(months_between(sysdate, csrq)/12) AS "Age" FROM wrxxb; --算法二: SELECT trunc(to_number(to_char(sysdate,'yyyymmdd'))/10000 - to_number(to_char(to_date('1982-8-28','yyyy-mm-dd'),'yyyymmdd'))/10000) FROM dual; -

两个Date类型字段:START_DATE,END_DATE,计算这两个日期的时间差(分别以天,小时,分钟,秒,毫秒): 天: ROUND(TO_NUMBER(END_DATE - START_DATE)) 小时: ROUND(TO_NUMBER(END_DATE - START_DATE) * 24) 分钟: ROUND(TO_NUMBER(END_DATE - START_DATE) * 24 * 60) 秒: ROUND(TO_NUMBER(END_DATE - START_DATE) *

一.天数: 在Oracle中,两个日期直接相减,便可以得到天数: select to_date('08/06/2015','mm/dd/yyyy')-to_date('07/01/2015','mm/dd/yyyy') from dual; 二.月数: 计算月数,需要用到months_between函数: select months_between(to_date('01/31/2015','mm/dd/yyyy'),to_date('12/31/2014','mm/dd/yyyy')) "MO

Oracle 数据库使用 sql语句 :    select lengthb('输入字符串') from dual  ,  来计算 字符串 所占的字节长度(比如,一个汉字3个字节),但是用这个lengthb函数时,输入字符串的长度不能超过4000,这样遇到一些超长字符串就不行了,因此,需要用下面的三个vb.net函数来配合获取: Private Function getStrLength_long(strInput As String) As Integer 'Try Dim list_strs

查询某月有多少天.代码例如以下: select to_number(add_months( trunc(to_date('2014-11-4 11:13:53','yyyy-mm-dd hh24:mi:ss'),'mm'),1) - trunc(to_date('2014-11-4 11:13:53', 'yyyy-mm-dd hh24:mi:ss'),'mm')) daycount from dual; select to_number(add_months( trunc(to_date(to

oracle如何计算两个日期的相差天数.月数.年数.小时数.分钟数.秒数 1.相差天数(两个日期相减) --Oracle中两个日期相差天数-- select TO_NUMBER(TO_DATE('2018-6-5','yyyy-mm-dd hh24:mi:ss')- TO_DATE('2018-5-31','yyyy-mm-dd hh24:mi:ss')) AS 相差天数 from dual; 2.相差小时数.分钟数.秒数 --Oracle中两个日期相差小时数-- ) AS 相差小时数 from

' second as TSec from dual -- 计算 60秒 前的时间 ' minute as TMin from dual -- 计算 10分 前的时间 ' hour as UTCTime from dual -- 计算 8小时 前的时间 / as UTCTime from dual -- 计算 8小时 前的时间 select sysdate - interval '8 2' day to hour as UTCTime from dual -- 计算 8天2小时 前的时间 sel

--计算平闰年天数函数 CREATE OR REPLACE FUNCTION f_ping_run_nian (i_year NUMBER --定义函数名 ) RETURN VARCHAR2 IS --定义返回(输出)字符类型 v_tianshu ); --定义输出(返回)变量 BEGIN SELECT ) --取除以4的余数 --如果是0,则是闰年,应为366天 ' ELSE ' --否则为365天 END INTO v_tianshu from dual; --将值插入变量种 RETURN

CREATE Function Dbo.GetAge ( @birthday datetime, @now datetime ) Returns int As Begin Declare @Age int, @year int, @month int, @Day int Set @age = Set @year = Set @month = Set @day = Set @year = DatePart(Year,@Now) - DatePart(Year, @BirthDay) Set @mo

/* Formatted on 5/24/2012 4:15:58 PM (QP5 v5.149.1003.31008) */ SELECT deptno,       ename,                     --st_name || ' ' || last_name employee_name,       hiredate,      sal,        STDDEV (sal) OVER (PARTITION BY deptno ORDER BY hiredate) AS

日期相减,求天数 方法一: )),createdate from goods t

--方法1 select floor((sysdate - to_date('2006-09-01 08:00:00', 'yyyy-mm-dd hh24:mi:ss'))) as sDays from dual; --ceil(n) 取大于等于数值n的最小整数; --floor(n)取小于等于数值n的最大整数; select ceil(9.6) from dual; --->10 select floor(9.6) from dual; --->9 --方法2 select ROUND(TO

select a.catalog_name,decode(substr(trunc((a.s/b.count2),4)*100||'%',0,1),'.',replace(trunc((a.s/b.count2),4)*100||'%','.','0.'),trunc((a.s/b.count2),4)*100||'%') as percentfrom (SELECT PARENT_NAME as catalog_name, sum(COUNTNUM) as s      FROM RES_PR

select add_months(to_date('201202', 'YYYYMM'),1)-to_date('201202', 'YYYYMM') from dual

http://www.dba-oracle.com/t_find_size_schema.htm Question:  How do I find the size of a schema in my database? Answer: It depends on how you define "size".  If you want the total disk space consumed by the schema (including indexes, tablespace f

select trunc(months/12) || '岁' || trunc(mod(months, 12)) || '月' ||       trunc(sysdate - add_months(birth, trunc(months))) || '天' age  from (select months_between(sysdate, birth) months, birth          from (select date '2016-1-1' birth from dual));

1.在给定时间上加减天数 SQL> select to_char(to_date('20170531000000','yyyymmdd HH24:MI:SS')+4,'YYYYMMDDHH24MISS' )from dual ; ---->20170604000000 2.在给定时间上加减小时数 SQL>select to_char(to_date('20170531000000','yyyymmdd HH24:MI:SS')+2/24,'YYYYMMDDHH24MISS') from

1.months_between(date1,date2);date1和date2相减得到相差的月份. select months_between(to_date('2015-05-11','yyyy-MM-dd'),to_date('2015-04-11','yyyy-MM-dd')) from dual :相差一个月. 2.ceil(date1-date2);date1-date2相减得到相差的天数 select ceil(To_date('2015-05-11 00:00:00' , 'y

Oracle函数可以实现诸多的功能,下面就介绍使用oracle函数计算时间差的实现方法. 两个Date类型字段:START_DATE,END_DATE,计算这两个日期的时间差(分别以天,小时,分钟,秒,毫秒): 天: ROUND(TO_NUMBER(END_DATE - START_DATE)) 小时: ROUND(TO_NUMBER(END_DATE - START_DATE) * 24) 分钟: ROUND(TO_NUMBER(END_DATE - START_DATE) * 24 * 60

在Oracle中计算两个日期间隔的天数.月数和年数: 一.天数: 在Oracle中,两个日期直接相减,便可以得到天数: select to_date('08/06/2015','mm/dd/yyyy')-to_date('07/01/2015','mm/dd/yyyy') from dual; 返回结果:36 二.月数: 计算月数,需要用到months_between函数: --months_between(date1,date2) --如果两个日期中“日”相同,或分别是所在月的最后一天,那么返

create or replace function Fuc_Get_AuthorName(RecID_In in varchar2, AdmID_In in varchar2) return varchar2 is Result varchar2(8000); names varchar2(4000); Cursor Cur_Get_AuthorNameS Is SELECT PEOPLENAME From TB_NEWS_CONTRI_AUTHOR Where REC_ID=RecID_In