获取表名: Oracle的user_talbes用于记录了用户表信息. select * from user_tables 获取某个表的字段: USER_TAB_COLS中记录了用户表的列信息.下面是别人写的: SELECT USER_TAB_COLS.TABLE_NAME as 表名,USER_TAB_COLS.COLUMN_NAME as 列名 , USER_TAB_COLS.DATA_TYPE as 数据类型, USER_TAB_COLS.DATA_LENGTH as 长度, USER
方法1: --Oracle 根据字段值查询其所在的表.字段 DECLARE CURSOR cur_query IS SELECT table_name, column_name, data_type FROM user_tab_columns; a NUMBER; sql_hard VARCHAR2(); vv NUMBER; BEGIN FOR rec1 IN cur_query LOOP a:=; IF rec1.data_type ='VARCHAR2' OR rec1.data_type
1.select 表中重复的字段 from 表名 group by 表中的重复的字段 HAVING count(表中的重复的字段)>1 举例说明 : 表名 : psp_cell_model 重复的字段名:mp_no select mp_no from psp_cell_model group by mp_no HAVING count(mp_no)>1; 举例2: select * from psp_cell_model where mp_no in( select mp_no
1.将表名和字段名改为大写 见--http://www.cnblogs.com/wenboge/articles/4121331.html 2.将表名和字段名改为小写 ①改表名为小写 begin for c in (select table_name tn from user_tables where table_name <> lower(table_name)) loop begin execute immediate 'alter table '||c.tn||' rename to
表是否存在: select count(*) from user_tables where table_name = #{tablename} 包含某个字段的表 select * from user_tab_columns where UPPER(column_name)='CREATE_TIME' 特定表是否包含字段 select * from user_tab_columns where UPPER(column_name)='CREATE_TIME' AND TABLE_NAME = 'S