#update 和 select在同一张表的时候会显示冲突 报错信息: [Err] 1093 - You can't specify target table 'tb_a' for update in FROM clause update tb_a set sex='boy' where uid =(select uid from tb_a where name ='cyq') #解决方式:嵌套多一个查询表 update tb_a set sex='boy' where uid =(selec
转载:http://www.cnblogs.com/nizuimeiabc1/p/9441937.html 1,首先查找表的操作记录 select * from v$sqlarea a where a.SQL_TEXT like '%TB_ACCT_SYSDATE%'; 2,从上面的记录中找到update语句对应的sql_id select * from v$sqltext a,v$sqlarea b where a.SQL_ID=b.SQL_ID and b.SQL_ID in('cq5382
第一个sql语句 select companyname gsmc,zb zhibiao from t_gsndzb left join t_companycode on t_gsndzb.gsbh=t_companycode.companyid 查询结果: 第二个sql语句 ,) ,)) ndje FROM t_xstj left join t_companycode on t_companycode.companyid = t_xstj.gsbh group by gsbh 查询结果: 合并成
Oracle没有update from语法,可以通过四种写法实现同样的功能: 一.标准update语法(常用.速度可能最慢) 当更新的表示单个或者被更新的字段不需要关联表带过来,此法是最好的选择. update a set a.c2= (select b.c2from b where a.c1=b.c1) ') as M set ac2=bc2 三.merge更新法 (关联字段非主键时,速度较快) merge是oracle特有的语句,语法如下: MERGE INTO table_name ali
update两表关联的写法包括字查询 1.update t2 set parentid=(select ownerid from t1 where t1.id=t2.id); 2. update tb_client_win_lost_report a set a.rolling_code_id=2 where game_code_id=70000 and exists (select 'x' from (select a.id from (select id,level_ from tb_adm
如下:一张订单表多个字段关联用户表: 1.链表查询 SELECT cu.id AS 'id',cu.version AS 'version',cu.cid AS 'cid',cu.uid AS 'uid',cu.shopName AS 'shopName',cu.address AS 'address', cu.totalPrice AS 'totalPrice',cu.orderType AS 'orderType', cu.state AS 'state',cu.cCreateTime AS
转自https://blog.csdn.net/anxpp/article/details/73173274 update table1 t1 left join table2 t2 on t1.key=t2.key set t1.field1=t2.field1, t1.field2=t2.field2, t1.field3=t2.field3 where t1.field4 is null and t2.field4 > '2017-04-27';
create user JSETI_WZQ identified by abcdef; -- 假设abcdef是密码 grant connect,resource to JSETI_WZQ; grant select on LYSDC.ly_xxbz_gxjg_grtxfszl to JSETI_WZQ; grant select on LYSDC.ly_xxbz_gxjg_jzgjcsjzl to JSETI_WZQ; grant select on LYSDC.LY_XXBZ_GXXX_DW
SELECT vtiger_orderitem.orderid, ( SELECT vtiger_users.last_name FROM vtiger_users WHERE vtiger_orderitem.signatory = vtiger_users.id ) AS signatory, ( SELECT vtiger_users.last_name FROM vtiger_users WHERE vtiger_orderitem.servicer = vtiger_users.id