<if test="status !=null and status !='' and status =='1'.toString()"> ORDER BY tag.create_time DESC</if><if test="status !=null and status !='' and status =='2'.toString()"> ORDER BY tag.create_time ASC</if>

正常查询语句中TOP的运用: SELECT TOP 1000 * FROM MP_MemberGrade   随意更新一张表中满足条件的前N条数据: UPDATE TOP (1) MP_Member SET FKGradeID=2 WHERE IsDeleted=2   更新A表中满足B表前N条记录的数据 UPDATE MP_Member SET FKGradeID=2 FROM MP_Member A LEFT JOIN (SELECT TOP 10 * FROM MP_MemberGrade

1391: [Ceoi2008]order Time Limit: 10 Sec  Memory Limit: 64 MBSubmit: 1509  Solved: 460[Submit][Status][Discuss] Description 有N个工作,M种机器,每种机器你可以租或者买过来. 每个工作包括若干道工序,每道工序需要某种机器来完成,你可以通过购买或租用机器来完成. 现在给出这些参数,求最大利润 Input 第一行给出 N,M(1<=N<=1200,1<=M<=12

1Add JAR 从Eclipse的现有所有工程中,添加jar包到该工程下 2Add External JARs 从Eclipse外的其他的位置,添加jar包到该工程下 3Add Variable 增加一个变量 4Add Library 增加一个库 5Add Class Folder 从Eclipse的现有所有工程中,增加一个class文件夹 6Add External Class Folder 从Eclipse的外,增加一个class文件夹 7 Order and Export Order a

linux 环境下运行ECLIPSE时 出现 “ A Java Runtime Environment (JRE) or Java Development Kit (JDK) must be available in order to run STS. No Java virtual machine was found after searching the following locations: /home/carlos/Documents/soft/sts-bundle/sts-3.7.3

order by 排序查询.asc升序.desc降序 示例: select * from 学生表 order by 年龄 ---查询学生表信息.按年龄的升序(默认.可缺省.从低到高)排列显示 也可以多条件排序. 比如 order by 年龄,成绩 desc 按年龄升序排列后.再按成绩降序排列 group by 分组查询. having 只能用于group by子句.作用于组内,having条件子句可以直接跟函数表达式.使用group by 子句的查询语句需要使用聚合函数. 示例: select

order by  跟在select* from 后面 order by 默认的是升序, asc 升序  desc 降序 select * from 表名 order by  字段名  asc 在带有过滤条件的情况下, 跟在where后面 select * from A where  Age>23 order by Salary desc

今天遇到一个关于SQL转换成Oracle语句的问题,描述如下: select * from emp order by deptno; select * from dept; Sql Server: update dept a set dname=(select top 1 ename from emp where deptno=a.deptno order by sal) 经过尝试,查找资料,得出下面转换结果,不知道这样是否可行: update dept a set dname= (with t

Sept. 5, 2015 花时间把代码读明白, 比光看书强. 动手写代码, 改代码,  兴趣是最好的老师. 多记几个例子, 增加情趣. 举个例子关于中序遍历,            4         /     \        2       6      /  \     / \     1   3   5   7  easy way to travel is to remember the order of its position in the horizontal way     

Sept. 13, 2015 Spent more than a few hours to work on the leetcode problem, and my favorite blogs about this problems: 1. http://siddontang.gitbooks.io/leetcode-solution/content/tree/construct_binary_tree.html 2.http://blog.csdn.net/linhuanmars/artic

Given integers n and k, find the lexicographically k-th smallest integer in the range from 1 to n. Note: 1 ≤ k ≤ n ≤ 109. Example: Input: n: 13 k: 2 Output: 10 Explanation: The lexicographical order is [1, 10, 11, 12, 13, 2, 3, 4, 5, 6, 7, 8, 9], so

Given a binary tree, return the vertical order traversal of its nodes' values. (ie, from top to bottom, column by column). If two nodes are in the same row and column, the order should be from left to right. Examples: Given binary tree [3,9,20,null,n

Suppose that a website contains two tables, the Customers table and the Orders table. Write a SQL query to find all customers who never order anything. Table: Customers. +----+-------+ | Id | Name | +----+-------+ | 1 | Joe | | 2 | Henry | | 3 | Sam

Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from left to right, level by level from leaf to root). For example:Given binary tree {3,9,20,#,#,15,7}, 3 / \ 9 20 / \ 15 7 return its bottom-up level order tr

Given a binary tree, return the zigzag level order traversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between). For example:Given binary tree {3,9,20,#,#,15,7}, 3 / \ 9 20 / \ 15 7 return its

Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example:Given binary tree {3,9,20,#,#,15,7}, 3 / \ 9 20 / \ 15 7 return its level order traversal as: [ [3], [9,20], [15,7] ] 层序

今天配置开启Apache虚拟主机时, 然后日志报错提示: Invalid command 'Order', perhaps misspelled or defined by a module not included in the server config 解决方法: 把 #LoadModule access_compat_module modules/mod_access_compat.so 前面改成: LoadModule access_compat_module modules/mod_

ORDER BY子句必须出现在SELECT中的最后一个子句. 在排序的列中NULL值被认为是最大的. 在SQL语句中给表达式定义别名是一个好习惯. 多列排序时不管升序还是降序,每个列需要单独设置

select * from production;alter table production add productionprice number(7,2); UPDATE production set productionprice=102.23--查询语句-- subStr 用来分割字段 1 为起始位置也就是第一个字,2位结束位置-- 字段名称后直接跟 汉字或者其他的注释信息 为查询后的 列头select subStr(productname,1,2) 产品名称, quantity 原价,

(1) 排序控制 select TABLE_NAME, TABLESPACE_NAME from user_tables order by TABLE_NAME $ordertype$ Where the user input ordertype ASC, DESC. On this keyword, use the $ordertype: SQLKEYWORD$ replacement $ ordertype $. (2)排序字段 sql statement metadata. If the

http://www.geeksforgeeks.org/print-binary-tree-vertical-order/ package algorithms; import java.util.ArrayList; import java.util.List; import java.util.Map; import java.util.TreeMap; public class PrintVertical { private static TreeMap<Integer, List<T