思路:看到题目首先想到最大字符串匹配KMP算法 public static int lengthOfLongestSubstring(String s) { int maxLength = 0; StringBuilder sb = new StringBuilder(s); a:for(int i = 0;i<sb.length();i++){ StringBuilder sb2 = new StringBuilder(""); sb2.append(sb.substring(
Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longest subst
Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longest subst
java中substring的使用方法 str＝str.substring(int beginIndex);截取掉str从首字母起长度为beginIndex的字符串,将剩余字符串赋值给str: str＝str.substring(int beginIndex,int endIndex);截取str中从beginIndex開始至endIndex结束时的字符串,并将其赋值给str; 下面是一段演示程序: public class StringDemo{ public static void main
C#的SubString(); 例子: string str = "i am a girl"; string temp = str.Substring(2,2);//从索引2开始,截取长度为2的字符串(索引的起始下表是0) //结果是 am 注意:截取的长度不能比剩下的字符串还要长,否则会报错: Substring: index and length must refer to a location within the string 错误的原因是超出了字符串的长度,如上面的例子:st
题目: You are given a string, S, and a list of words, L, that are all of the same length. Find all starting indices of substring(s) in S that is a concatenation of each word in L exactly once and without any intervening characters. For example, given:
