一句话判断 [ ! $a ] && echo "a is null" 1.判断变量 read -p "input a word :" word if [ ! -n "$word" ] ;then echo "you have not input a word!" else echo "the word you input is $word" fi 或者 #!/bin/sh a= if [ !
ok,以后最好是每天一个shell小脚本吧,这样以后工作时还可以直接套用,嗯,比较不错,顺便还可以带给刚入门shell的朋友一些帮助,好了,废话不多说,下面是我两种判断的实现方式: 1.通过grep去筛选非数字,判断其输出状态,以下两种方式: #!/bin/bashread -p "please input a num: " num if echo $num | grep -q '[^0-9]' then echo "this is not a num,please inpu
核心代码 #!/bin/sh myPath="/var/log/httpd/" myFile="/var /log/httpd/access.log" #这里的-x 参数判断$myPath是否存在并且是否具有可执行权限 if [ ! -x "$myPath"]; then mkdir "$myPath" fi #这里的-d 参数判断$myPath是否存在 if [ ! -d "$myPath"]; then
1. shell 的$! ,$?, $$,$@ $n $1 the first parameter,$2 the second... $# The number of command-line parameters. $0 The name of current program. $? Last command or function's return value. $$ The program's PID. $!
http://blog.chinaunix.net/uid-7553302-id-183648.html 1 shell 的$! ,$?, $$,$@ $n $1 the first parameter,$2 the second... $# The number of command-line parameters. $0 The name of current program. $? Last command or function'
1.判断字符串为空 if [ -z "$str" ]; then echo "empty string" fi 2.判断文件是否存在 if [ -f /home/builder/.profile ]; then echo "File exists;" fi 3.逻辑非 if [ ! -f /home/builder/.bash_profile ]; then echo "here!"else echo "te