自定义排序需要单独写一个compare函数 例1 LeetCode 056. Merge Intervals Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. /** * Definition for an interval. * struct Interval { *
题目如下: A long-distance telephone company charges its customers by the following rules: Making a long-distance call costs a certain amount per minute, depending on the time of day when the call is made. When a customer starts connecting a long-distance
# 给三个数字排序# 方法一def sort_d(a,b,c): if a>b: a,b=b,a # print (a,b) if b>c: b,c=c,b if a>b: a,b=b,a return a,b,c print(sort_d(1,2,3))print(sort_d(11,2,3))print(sort_d(12,2,-13)) 第二种方法: def sort_new(a,b,c): if a>b: a,b=b,a if b>c: b,c=c,b if a>
使用STL库sort函数对vector进行排序,vector的内容为对象的指针,而不是对象. 代码如下 #include <stdio.h> #include <vector> #include <algorithm> using namespace std; class Elm { public: int m_iSortProof; private: int __m_iValue; static int __m_iCnt; public: Elm(); int get