尊重原创:http://blog.csdn.net/love_java_cc/article/details/52234889 有表如下table3: 需要查询country中各个国家出现的次数 SQL语句: SELECT country as 国家,COUNT(*) as 次数 FROM table3 GROUP BY country 结果如下: 知识点: count(*)统计的是结果集的总条数,count(字段名)统计的是该字段值不为null的总条数 Group By:从字面意义上理解就是根
假设表结构:用户名,日期,上班时间,下班时间.8月份记录:select * from 表名 where month(日期)=8 and 用户名 = '小张'8月份迟到早退次数:select sum(iif(datediff('s','8:00',上班时间) > 0,1,0)) as 迟到次数,sum(iif(datediff('s','17:00',下班时间) < 0,1,0)) as 早退次数 from 表名 where month(日期) = 8 and 用户名 = '小张' select
oracle中的clob类型字段不能直接显示出来,需要借助Oracle系统dbms_lob中substr方法处理,如select dbms_lob.substr(clobField) from table 如果内容输出不全,进行如下设置 set heading off 不输出结果第一行的标题 (字段名称) set long 40000 设置输出的字节数(比较大数)
select count(姓名) as 重复次数,姓名from 某表 group by 姓名order by 重复次数 asc 首先,group by 姓名,可以将所有相同姓名的项集合在一起.然后,count(姓名),将姓名次数进行统计,然后作为重复次数,最后,order by通过重复次数排序,asc表示排序为由小到大,即递增顺序.
),jbrq, ),'/','-')as jbrq, ' then '启用' when ' then '未启用' else '修改' end cbzt,shzt from jc_yscbfxb select zxmid,row_number() over(order by xm.zzjgfhid,zxmmc) as xh,zxm.xmid,xmmc,zxmmc,htzj,zxm.fzrid,rs.ygmc, ' then '启用' else '未启用' end flag,zxm.bz from
SELECT * FROM dbo.SBD_WAYBILL_GOODS WHERE WG_SW_ID ) ORDER BY WG_ID SELECT * FROM dbo.SBD_WAYBILL WHERE SW_JOURNAL_NUMBER ) SELECT DISTINCT SW_JOURNAL_NUMBER FROM dbo.SBD_WAYBILL DELETE dbo.PDA_ERROR WHERE PE_ERRORVALUE IN(SELECT MAX(PW_ID) ) SELECT
SELECT dbid,count() FROM [Master].[dbo].[SYSPROCESSES] WHERE spid> and status='sleeping' group by dbid order by count() desc and waittype = 0x0000 and waittime = and status = 'sleeping' and last_batch < dateadd(minute, -, getdate()) and login_time &
SQL Server中查询CPU占用高的情况,会用到sys.sysprocesses ,dm_exec_sessions ,dm_exec_requests 一.查看当前的数据库用户连接有多少 USE master GO SELECT * FROM sys.[sysprocesses] WHERE [spid]>50 --AND DB_NAME([dbid])='gposdb' SELECT COUNT(*) FROM [sys].[dm_exec_sessions] WHERE [sessio