select whbmbh ,zt,1 as tjsl from fyxx group by zt,whbmbh select whbmbh,sum(case zt when '有效' then 1 end) as yxsl,sum(case zt when '暂缓' then 1 end )as zhsl,sum(case zt when '未知' then 1 end) as wzsl,sum(case zt when '我租' then 1 end) as wzsl,sum(case zt

sql 分组后显示每组的前几条记录 如   表中记录是             code       serialno             A1               1             A1               2             A1               3             A1               5                 B1               2             B1               3

原文:sql 分组后按时间降序排列再取出每组的第一条记录 竞价记录表: Aid 为竞拍车辆ID,uid为参与竞价人员ID,BidTime为参与竞拍时间 查询出表中某人参与的所有车辆的最新的一条的竞价记录 思路:通过aid分组,通过时间做降序排列,给每组数据加上行号(rowId)然后取出行号为1的数据,就是所要查询的数据 源数据: select * from auto_AuctionRecords 执行查询后的数据: select * from (select ROW_NUMBER()over(p

本示例测试两个表联接查询后,分组并取分组后的最小行号记录 测试表: tb1表结构如下: CREATE TABLE [dbo].[tb1]( ) NOT NULL, ) NULL, ) NULL, CONSTRAINT [PK_tb1] PRIMARY KEY CLUSTERED ( [a] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, AL

1.取时间最新的记录 不分组有重复(多条CreateTime一样的都是最新记录) select * from test t where pid in ( select PId from Test t where time=(select max(time) from Test t1 where t1.PId=t.PId) group by Pid ) and time=(select max(time) from Test t1 where t1.PId=t.PId) 2.分组后取时间最新的记录

--有id,name,createDate的一张表testTable--根据name分组,获取每组中createDate最大的那条记录(整条)查询出来---------------------------------------------- 创建一张表,语句如下: CREATE TABLE [dbo].[testTable] ( [id] [int] NOT NULL IDENTITY(1, 1), [name] [nchar] (10) COLLATE Chinese_PRC_CI_AS N

语法:ROW_NUMBER() OVER(PARTITION BY COLUMN ORDER BY COLUMN) 简单的说row_number()从1开始,为每一条分组记录返回一个数字,这里的ROW_NUMBER() OVER (ORDER BY xlh DESC) 是先把xlh列降序,再为降序以后的没条xlh记录返回一个序号. 示例: xlh           row_num 1700              1 1500              2 1085             

/* 分组之后拼接字符串 */ ;with t as( SELECT WorkflowId,Remark FROM dbo.OperatorAutomationProcess GROUP BY WorkflowId,Remark ) , H AS( SELECT WorkflowId, -- 分组的主键 STUFF( ( SELECT '_'+ Remark -- 要拼接的列 FROM t a WHERE b.WorkflowId = a.WorkflowId FOR XML PATH('')

with t as( select 'Charles' parent, 'William' child union select 'Charles', 'Harry' union select 'Anne', 'Peter' union select 'Anne', 'Zara' union select 'Andrew', 'Beatrice' union select 'Andrew', 'Eugenie' ) SELECT parent, STUFF( ( SELECT ','+ chil

SELECT ID,Name,Class ROW_NUMBER() OVER(PARTITION BY Class ORDER BY ID) as NUM 主要是用到 rownum 里面的 PARTITION BY 函数  使用class分组,id排序 .每个分组查询前9个

场景:sql server 2008 drop table ID CREATE TABLE ID ( id ,) not null, code int , D date, PRIMARY KEY (id) ) ,getdate()) ,getdate()) ,getdate()) ,getdate()) ,'2017-08-02') ,'2017-08-01') select * from ID 目标: select COUNT(*) from ID group by code 产生code列唯

select  row_number() over(partition by  CODE order by SEQUENCE) as RowIndex  from Table 注:根据表的CODE 字段分组,组内根据SEQUENCE字段排序,生成序号 RowIndex

CREATE TABLE students (course varchar(10), stu_name varchar(10), city varchar(10), score int ) insert into students values('数学','Jack','Tianjin',80); insert into students values('数学','Jordan','Tianjin',80); insert into students values('数学','James','B

select gr,num,dt,(select bys from test where gr=b.gr and dt=b.dt) bys from ( select gr,count(0) num,max(dt) dt from test group by gr ) b //如果有重复项,可用如下语句(针对Mysql的limit,Oracle 可用 rownum<2) select gr,num,dt,(select bys from test where gr=b.gr and dt=b.d

/****** Object: Table [dbo].[TEMP] Script Date: 2018-8-22 星期三 23:33:09 ******/ SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO CREATE TABLE [dbo].[TEMP]( [ID] [nvarchar](36) NULL, [SerialNo] [nvarchar](36) NULL, [Qty] [numeric](10, 1) NULL, [Foreign

select convert(char(8),[UseTime],112) dt,sum([UseMoney]) 合计,sum(case when [S_Number]=2 then UseMoney else 0 end ) as '状态2', sum(case when [S_Number]=3 then UseMoney else 0 end ) as '状态3'from [TX_DB].[dbo].[Fjc_Money_User]group by convert(char(8),[Use

SELECT * FROM( SELECT id,name,counts,createDate,row_number() OVER(partition BY name ORDER BY createDate DESC) rowno FROM testTable ) t

一.分组查询1.使用group by进行分组查询在使用group by关键字时,在select列表中可以指定的项目是有限制的,select语句中仅许以下几项:〉被分组的列〉为每个分组返回一个值得表达式,例如用一个列名作为参数的聚合函数group by的使用在这只写几个例子吧:例:select courseID,avg(score) as 课程平均成绩from scoregroup by courseID例:select studentID as 学员编号,courseID as 内部测试,avg

as tjsl from fyxx group by zt,whbmbh end) as ybhsl from fyxx group by whbmbh 下面是摘自别人的博客 最近遇到一个问题,需要对一张表做统计,这个统计有什么特别之处值得我记录了下来呢?大家知道SQL中聚合函数GROUP BY的结果一般为一列,即多个值通过聚合函数运算统计到一起,但是如何将不同条件的值统计到不同列中呢,即按条件统计到多个列中.举个栗子: YEAR TYPE VALUE 2015 1 100 2015 2 200