library(dplyr) unite(mtcars, "vs_am", vs, am) Merging Data Adding Columns To merge two data frames (datasets) horizontally, use the merge function. In most cases, you join two data frames by one or more common key variables (i.e., an inner joi
Expression构建DataTable to Entity 映射委托 1 namespace Echofool.Utility.Common { 2 using System; 3 using System.Collections.Generic; 4 using System.Data; 5 using System.Linq.Expressions; 6 using System.Reflection; 7 using System.Reflection.Emit; 8 9 publ
SQL中只有两列数据(字段1,字段2),将其相同字段1的行转列 转换前: 转换后: --测试数据 if not object_id(N'Tempdb..#T') is null drop table #T Go Create table #T([MDF_LOT_NO] int,[ERP_MODE_CD] int) Insert #T , union all , union all , union all , Go --测试数据结束 DECLARE @name VARCHAR(max),@sql
[字符合并多行为一列] 思路1:行转列,在与字符拼接(适用每组列数名相同) 思路2:转xml,去掉多余字符(适用所有) 假设兴趣表Hobbys Name Hobby 小张 打篮球 小张 踢足球 Name Hobby 小张 打篮球,踢足球 [思路1]注意:此方法只是用分组里行数内容固定的情况,如学科:语文,英语,数学. select Name,打篮球+','+踢足球 AllHobby from (select * from Hobbys pivot (Hobby for Hobby in (打篮球
看图说话比较直观: 对比复制前后的数据表: 使用SQL语句:UPDATE OR ROLLBACK Content SET YINBIAO = YINBIAO2, GESHU = GESHU2 WHERE YINBIAO2 IN (SELECT YINBIAO2 FROM Content WHERE PINYIN LIKE 'b%')
首先是源数据: ),cip.CheckIn_StartTime, )),cip.CheckIn_EndTime, )),cip.Rental_Price)) as content from CheckInPeriod cip 然后我们加上合并语句: ),content) from ( ),cip.CheckIn_StartTime, )),cip.CheckIn_EndTime, )),cip.Rental_Price)) as content from CheckInPeriod cip )
#移动数据 UPDATE dcs_organize_user AS a, dcs_organize_user AS b SET a.SHORTTELNO=b.USERTELNO WHERE a.id=b.id; #字段加前缀 UPDATE dcs_organize_user SET USERTELNO=CONCAT(',USERTELNO);
示例sql: <update id="receipt" parameterType="com.pisen.cloud.luna.ms.security.code.base.mapper.beans.ReceiptBean"> update security_code_info info LEFT JOIN security_code_relation re ON re.security_code = info.security_code set info
begin ),(, ))) from workplan a join org_employee b on b.id = a.idowner , LEN(aa.sglzbbh))) glh from workplan aa group by aa.idowner ) c on c.id = a.idowner where a.id = '${targetID}' --自动关联上周计划编号 --自动关联上周计划编号 update a set a.idszzb = b.id from workpla
把一列数据拼接成一个字符串比较简单: declare @test varchar(500) set @test=''; select @test=@test+name+',' from person select @test 但是如果数据中有重复选项,想去掉重复的就比较绕弯了. ) set @test=''; select distinct @test=@test+name+',' from person select @test 加distinct是不行的,我在sql server 2008
