SQL查询记录中增加序列号 根据学生成绩在查询结果中增加排名字段: 1.SELECT ROW_NUMBER() OVER (ORDER BY SCORE ASC) AS RANK,NAME,SCORE FROM GRADE ORDER BY SCORE; 此写法是直接在结果记录添加顺序排序序号 2.SELECT RANK() OVER (ORDER BY SCORE ASC) AS RANK,NAME,SCORE FROM GRADE ORDER BY SCORE; 此写法的根据排序依据列的值进
select a.id as aid,b.id as bid,a.city,a.cang,a.sid,a.time as atime,b.time as btime,a.price as aprice,b.price as bprice,a.pm as apm,b.pm as bpm from (select id,city,cang,sid,time,price,@rank:=@rank+1 as pm from cai,(SELECT @rank:=0) B group by id,ci
select order_id FROM yzj_store_order t WHERE (t.user_id,t.order_status) IN ( SELECT user_id,order_status FROM yzj_store_order where order_status=0 AND DATE_FORMAT( create_date, '%Y-%m-%d' ) = DATE_FORMAT( CURDATE( ) - 0, '%Y-%m-%d' ) GROUP BY user_id
Farmer John's N cows (1 ≤ N ≤ 100,000) share many similarities. In fact, FJ has been able to narrow down the list of features shared by his cows to a list of only K different features (1 ≤ K ≤ 30). For example, cows exhibiting feature #1 might have s
给查询出的SQL记录添加序号列,解决方法有以下两种 第一: select ROW_NUMBER() OVER (ORDER BY a.字段 ASC) AS XUHAO,a.* from table a (table 为表名,字段为表a中的字段名) 第二: select RANK() OVER (ORDER BY a.字段 ASC) AS XUHAO,a.* from table a (table 为表名,字段为表a中的字段名) 出处:http://blog.csdn.net/xsfqh/a
1 前言 项目中排行榜刚好需要查数据库表然后给出编号,方案一,可以按条件查找出来,然后再按数组序号给编号,但是如果要查表出来直接看,就不太够用了:方案二,就是用代码帮忙编号.参考了网上一些代码,然后发现方法都有一个样的,然后这边只是作为记录使用,方便查找. 2 代码 SELECT province_id, province_name, gdp, (@i :=@i + 1) AS No FROM province, (SELECT @i := 0) AS it ORDER BY gdp DESC