前提:相同的数据重复往数据库写入,导致存在仅主键Id不同的重复数据,现在需要去除重复数据,仅保留重复数据中Id最大的一条 思路: 1.找出存在重复数据的记录,并取重复数据中最大的Id值 2.删除记录中不包含最大Id值的记录 注意:该SQL会删除没有重复数据的记录 实现: DELETE FROM [Log_IIS].[dbo].[IISLog_table] WHERE id not in (select MAX(Id) from [IISLog_table] group by [Re
Access数据库删除重复记录,只保留一条记录的做法: 只保留id最小的记录方法: delete from [表名] where id not in (select min(id) from [表名] group by [带重复记录的字段名称]) 只保留id最大的记录方法: delete from [表名] where id not in (select max(id) from [表名] group by [带重复记录的字段名称])
删除重复数据保留name中id最小的记录 delete from order_info where id not in (select id from (select min(id) as id from order_info group by order_number) as b); delete from table where id not in (select min(id) from table group by name having count(name)>1) and id i
上图数据:SNum为”18004XXXXX000001K2GW 4000 L1C“,OffLineStation为“OP1010”的有两条数据,当where条件中为上述两者时会同时更新这两条数据,并不是我想要的. 更新要求:在上述条件下更新最新的一条记录 Id from RM_RepairOffLine where SNum = '18004XXXXX000001K2GW 4000 L1C' and OffLineStation = 'OP1010' order by CreationTime
项目中需要每次查询一个表中的最新的一条记录,表结构里面有日期字段.只需要显示一条记录. Mysql帮助文档里面的解释 3.6.2. 拥有某个列的最大值的行 任务:找出最贵物品的编号.销售商和价格. 这很容易用一个子查询做到: SELECT article, dealer, price FROM shop WHERE price=(SELECT MAX(price) FROM shop); 另一个解决方案是按价格降序排序所有行并用MySQL特定LIMIT子句只得到第一行: SELECT ar
1.查找表中多余的重复记录,重复记录是根据单个字段(Id)来判断 select * from 表 where Id in (select Id from 表 group byId having count(Id) > 1) 2.删除表中多余的重复记录,重复记录是根据单个字段(Id)来判断,只留有rowid最小的记录 DELETE from 表 WHERE (判断字段) IN ( SELECT 判断字段 FROM 表 GROUP BY 判断字段 HAVING COUNT(判断字段) > 1) A
最终代码 update T_Fee set gzl_dfg_op = 'delete' where MetReadRecordID in ( select MetReadRecordID from T_Fee and MetReadRecordID is not null group by MetReadRecordID ) and ID not in ( select min(ID) from T_Fee and MetReadRecordID is not null group by Met
DELETE FROM py_bond_shenzhen_exchange_opinion_2_1 WHERE id NOT IN (SELECT id FROM (SELECT min(id) AS id FROM py_bond_shenzhen_exchange_opinion_2_1 GROUP BY notice_date, notice_title) temp)