先来一个简单的sum select sum(qty) as total_qty from inventory_product group by product_id 这样就会统计出所有product的qty. 但是很不幸,我们的系统里面居然有qty为负值.而我只想统计那些正值的qty,加上if function就可以了. SQL为: select sum(if(qty > 0, qty, 0)) as total_qty from inventory_product group by produ
SELECT SUM(case WHEN sex=1 then 1 else 0 end )as '男生', SUM(case when sex =2 then 1 else 0 end )'女生'FROM asex 这句sql输出的就是男女生的人数(1代表男生,2代表女生),SUM(case WHEN sex=1 then 1 else 0 end )这句话的含义就是统计sex列中值为1的行数总和. 转自:https://blog.csdn.net/langwang1993/article/d
Problem:Given an array of integers, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please no
Max Sum Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 135262 Accepted Submission(s): 31311 Problem Description Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max s
Problem Description Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max sum of a sub-sequence. For example, given (6,-1,5,4,-7), the max sum in this sequence is 6 + (-1) + 5 + 4 = 14. Input The first line of the input contai
题目如下: Given an integer array arr and an integer k, modify the array by repeating it k times. For example, if arr = [1, 2] and k = 3 then the modified array will be [1, 2, 1, 2, 1, 2]. Return the maximum sub-array sum in the modified array. Note that
前言:本文以学习记录的形式发表出来,前段时间苦于照模型聚合中group by 找了很久,官方文章中没有很明确的说出group by,但在文档中有提到!!! 正文(最后编辑于2016-11-12): 聚合: LOrder.objects.values('com_chnl_name').annotate(Count('serv_id')) #相当于select count(serv_id) from LOrder group by com_chnl_name 模型高级运用—条件表达式+数据库函数:
