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leetcode 326. Power of Three(不用循环或递归) Given an integer, write a function to determine if it is a power of three. Follow up: Could you do it without using any loop / recursion? 题意是判断一个数是否是3的幂,最简单的也最容易想到的办法就是递归判断,或者循环除. 有另一种方法就是,求log以3为底n的对数.类似 如果n=9,则
发现一段经典SQL,不用循环游标,一句update代码实现滚动计算结存.为方便理解,结合实例测试之 --1,源数据#t1,jcshl初值为每个sid的当前库存数量,要实现的效果:每个sid的后一结存数量为前一jcshl结存数量-chkshl出库数量 SELECT * FROM #t1 ORDER BY sn sn plh sid chkshl jcshl1 S0002 20.0000 980.00002 S0003 10.0000 1010.00003 S0003 10.0000 1010.00