Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha
Given a string s consists of upper/lower-case alphabets and empty space characters' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space char
给定一个字符串, 包含大小写字母.空格 ' ',请返回其最后一个单词的长度.如果不存在最后一个单词,请返回 0 .注意事项:一个单词的界定是,由字母组成,但不包含任何的空格.案例:输入: "Hello World"输出: 5详见:https://leetcode.com/problems/length-of-last-word/description/ Java实现: class Solution { public int lengthOfLastWord(String s) { in