一:查询及删除重复记录的SQL语句1.查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断select * from peoplewhere peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)2.删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录delete from peoplewhere p
查询及删除重复记录的SQL语句 1.查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断select * from peoplewhere peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1) 2.删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录delete from people where
原文:随机取若干条记录的SQL语句 MySql中随机提取数据库N条记录 select * from TableName order by rand() limit N SQLServer中随机提取数据库N条记录 select top N * from TableName order by NEWID() Access中随机提取数据库N条记录 SELECT top N * FROM TableName ORDER BY Rnd(Id) Id:为你当前表的唯一ID字段名
1.首先,select top用法: 参考问题 select top n * from和select * from的区别 select * from table -- 取所有数据,返回无序集合 select top n * from table -- 根据表内数据存储顺序取前n条,返回无序集合 select * from table order by id desc -- 取所有数据,按id逆序返回有序列表 select top n * from table order by id desc--
查询及删除重复记录的SQL语句 1.查找表中多余的重复记录,重复记录是根据单个字段(Id)来判断 select * from 表 where Id in (select Id from 表 group byId having count(Id) > 1) 2.删除表中多余的重复记录,重复记录是根据单个字段(Id)来判断,只留有rowid最小的记录 DELETE from 表 WHERE (id) IN ( SELECT id FROM 表 GROUP BY id HAVING COUNT(id)
1.首先.select top使用方法: 參考问题 select top n * from和select * from的差别 select * from table -- 取全部数据.返回无序集合 select top n * from table -- 依据表内数据存储顺序取前n条,返回无序集合 select * from table order by id desc -- 取全部数据.按id逆序返回有序列表 select top n * from table order by id d
sql在不同数据库查询前几条数据 1. ORACLE SELECT * FROM TABLE_NAME WHERE ROWNUM <= N; HQL: from table_name t order by t.create_time desc where rownum<=n; 2. postgres查询前几条记录SQL SELECT * FROM TABLE_NAME LIMIT N; 3. DB2 SELECT * ROW_NUMBER() OVER(ORDER BY COL1 DESC
在工作中,我们经常需要检索出最新条数据,能够实现该功能的sql语句很多,下面列举三个进行效率对比 本次实验的数据表中有55万条数据,以myql为例: 方式1: SELECT * FROM t_device_monitor WHERE uploadTime in(select max(uploadTime) from t_device_monitor) 该语句平均耗时2.3秒 方式2: SELECT * FROM t_device_monitor WHERE uploadTime =(select
最近在网上找了下mysql查询随机的几个sql,我把最终的记录下来. SELECT * FROM uchome_mtag AS a JOIN (SELECT MAX(tagid) AS id FROM uchome_mtag) AS b ON (a.tagid>=FLOOR(b.id*RAND())) LIMIT 50 我试验后发现一个问题,当你的表里的总数和想要得到的条数很接近时,可能会不理想,有可能你有10条,你想查出随机的8条时,却只给出了5条的结果. 应该是那个大于等于造成的吧. 还有p
需要使用:分区函数用法(partition by 字段) select *,row_number() over(partition by item order by date ) as index from tab 分区索引 ------------------------------------------- SQL Server select * from (select * , row_number() over(partition by id order by state desc)
1.所有字段均重复的记录(重复记录保留一条) Select distinct * into #Tmp from tblName Drop table tblName Select * into tblName from #Tmp Drop table #Tmp 设计不周产生的,增加唯一索引可解决 2.所有字段均重复的记录(重复记录保留一条) Select distinct * into #Tmp from tblName Drop table tblName Select * into tblN
1.查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断select * from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1) 2.删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录delete from people where peopleId
Oracle: select * from (select * from tableName order by dbms_random.value) where rownum < N MS SQLServer: select top N * from tableName order by newid() My SQL: select * from tableName order by rand() limit N 原文:https://blog.csdn.net/senton/article/d
1.查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断 select * from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1) 2.删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录 delete from people where peopleId in (select
select Code, CodeName, CodeAlias, ComCode, OtherSign from ldcode where codetype = 'edorapptype' and code <> (case when (select 1 from lccont b where b.contno = 'W86190001290019' and b.trdingchannel like 'ZFB%') = 1 then '-9' else '9' end) and others