hdu 1054 Strategic Game(tree dp)
Strategic Game
Time Limit: 20000/10000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 3806 Accepted Submission(s): 1672
Your program should find the minimum number of soldiers that Bob has to put for a given tree.
The input file contains several data sets in text format. Each data set represents a tree with the following description:
the number of nodes
the description of each node in the following format
node_identifier:(number_of_roads) node_identifier1 node_identifier2 ... node_identifier
or
node_identifier:(0)
The node identifiers are integer numbers between 0 and n-1, for n nodes (0 < n <= 1500). Every edge appears only once in the input data.
For example for the tree:
the solution is one soldier ( at the node 1).
The output should be printed on the standard output. For each given input data set, print one integer number in a single line that gives the result (the minimum number of soldiers). An example is given in the following table:
0:(1) 1
1:(2) 2 3
2:(0)
3:(0)
5
3:(3) 1 4 2
1:(1) 0
2:(0)
0:(0)
4:(0)
2
#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
#define N 2010
int Min(int i,int j){return i<j?i:j;}
struct node{
node *l,*r;//l-son,r-brother
int f[2];
void init(){
l=r=NULL;f[0]=f[1]=0;
}
}t[N],*rt;
int r[N];
void dfs(node *x){
//遍历x儿子
node *l=x->l;
while(l){
dfs(l);
//放在x上
x->f[1]+=Min(l->f[0],l->f[1]);
//x不放
x->f[0]+=l->f[1];
l=l->r;
}
}
int main(){
int i,j,k,x,y,n,m;
while(~scanf("%d",&n)){
m=0;
memset(r,-1,sizeof(r));
while(n--){
scanf("%d:(%d)",&i,&k);
if(r[i]==-1){r[i]=m;t[m++].init();}
x=r[i];
while(k--){//i->l=j
scanf("%d",&j);
if(r[j]==-1){r[j]=m;t[m++].init();}
y=r[j];
t[y].f[1]=1;
t[y].r=t[x].l;
t[x].l=&t[y];
}
}
for(i=0;;i++)
if(t[r[i]].f[1]==0){
rt=&t[r[i]];
rt->f[1]=1;
break;
}
dfs(rt);
printf("%d\n",Min(rt->f[0],rt->f[1]));
}
return 0;
}
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