Read N Characters Given Read4 I & II
The API: int read4(char *buf) reads 4 characters at a time from a file.
The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file.
By using the read4 API, implement the function int read(char *buf, int n) that reads n characters from the file.
Note: The read function may be called only once.
public class Solution extends Reader4 {
public int read(char[] buf, int n) {
int index = ;
char[] tmp = new char[]; // temp buffer
while (index < n) {
int count = read4(tmp);
count = Math.min(count, n - index);
for (int i = ; i < count; i++) {
buf[index++] = tmp[i];
}
if (count < ) {
return index;
}
}
return index;
}
}
public class Solution extends Reader4 {
public int read(char[] buf, int n) {
boolean eof = false;
int charsRead = ;
char[] buf4 = new char[];
while (!eof && charsRead < n) {
int size = read4(buf4);
if (size < ) {
eof = true;
}
if (charsRead + size > n) {
size = n - charsRead;
}
System.arraycopy(buf4, , buf, charsRead, size);
charsRead += size;
}
return charsRead;
}
}
Read N Characters Given Read4 II - Call multiple times
The API: int read4(char *buf) reads 4 characters at a time from a file.
The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file.
By using the read4 API, implement the function int read(char *buf, int n) that reads n characters from the file.
Note: The read function may be called multiple times.
分析:
public class Solution extends Reader4 {
char[] buffer = new char[];
int bufferSize = , prevIndex = ;
public int read(char[] buf, int n) {
int index = ;
while (index < n) {
if (prevIndex < bufferSize) {
buf[index++] = buffer[prevIndex++];
} else {
bufferSize = read4(buffer);
prevIndex = ;
if (bufferSize == ) { break; }
}
}
return index;
}
}
public class Solution extends Reader4 {
private char[] buffer = new char[];
int offset = , bufsize = ;
public int read(char[] buf, int n) {
int readBytes = ;
boolean eof = false;
while (!eof && readBytes < n) {
int sz = (bufsize > ) ? bufsize : read4(buffer);
if (bufsize == && sz < ) eof = true;
int bytes = Math.min(n - readBytes, sz);
System.arraycopy(buffer, offset, buf, readBytes, bytes);
offset = (offset + bytes) % ;
bufsize = sz - bytes;
readBytes += bytes;
}
return readBytes;
}
}
Read N Characters Given Read4 I & II的更多相关文章
- [LeetCode] Read N Characters Given Read4 I & II
Read N Characters Given Read4 The API: int read4(char *buf) reads 4 characters at a time from a file ...
- [Locked] Read N Characters Given Read4 & Read N Characters Given Read4 II - Call multiple times
Read N Characters Given Read4 The API: int read4(char *buf) reads 4 characters at a time from a file ...
- [LeetCode] Read N Characters Given Read4 II - Call multiple times 用Read4来读取N个字符之二 - 多次调用
The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actu ...
- LeetCode Read N Characters Given Read4 II - Call multiple times
原题链接在这里:https://leetcode.com/problems/read-n-characters-given-read4-ii-call-multiple-times/ 题目: The ...
- 【LeetCode】158. Read N Characters Given Read4 II - Call multiple times
Difficulty: Hard More:[目录]LeetCode Java实现 Description Similar to Question [Read N Characters Given ...
- [LeetCode] Read N Characters Given Read4 用Read4来读取N个字符
The API: int read4(char *buf) reads 4 characters at a time from a file.The return value is the actua ...
- LeetCode Read N Characters Given Read4
原题链接在这里:https://leetcode.com/problems/read-n-characters-given-read4/ 题目: The API: int read4(char *bu ...
- [LeetCode] 157. Read N Characters Given Read4 用Read4来读取N个字符
The API: int read4(char *buf) reads 4 characters at a time from a file.The return value is the actua ...
- [LeetCode#157] Read N Characters Given Read4
Problem: The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is ...
随机推荐
- [Unity] Unity3D研究院编辑器之独立Inspector属性
本文转自: http://www.xuanyusong.com/archives/3680雨松MOMO Unity提供了强大的Editor功能, 我们可以很轻易的在EditorGUI中绘制任意的属性. ...
- centos 7.0 编译安装mysql 5.6.22 再次总结 成功编译安装~ 越来越熟练了~
查找php.ini文件所在位置 [root@localhost /]# find -name php.ini ./usr/etc/php/etc/php.ini mysql官网的安装说明http:// ...
- IE安全分析
IE安全问题,这个话题似乎很古老了,但是问题又是层出不穷~ 对于IE的安全,我个人认为有两点需要关注,一个是上网的安全,二个是IE解析代码的安全 对于IE上网安全,这是最基本的,也是最常用的了 附上一 ...
- Ajax load html page
jQuery ajax - load() 方法 jQuery Ajax 参考手册 实例 使用 AJAX 请求来改变 div 元素的文本: $("button").click(fun ...
- 固定导航(Sticky nav)
方法1: <div class="footer"></div> .footer{ position:fixed; bottom:0; left:0; wid ...
- YII2操作mongodb笔记(转)
componets配置: 'mongodb' => [ 'class' => '\yii\mongodb\Connection', 'dsn' => 'mongodb://test: ...
- vtk第一个程序
首先 设置环境变量 解决方案资源管理器 选中项目名字 而不是ALL_BUILD 选项卡 项目-属性 右侧 附加依赖项->编辑 kernel32.libuser32.libgdi32.libwin ...
- seajs的那点事(很坑的事),和本白的一点事(更坑的事)
在开始之前,偶先吐槽加逗比一下,2天前,CCAV的本白和百度的菊花成功潜入到了携程大楼 然后在没有找到他们运维的情况下,四处乱逛,企图把他们的服务器给root一下,然后再瞎逛之后到了一个很神奇的地方 ...
- 移动端网站优化指南-WAP篇
转载:http://seofangfa.com/mobile-seo/mobile-seo-guide.html 1.域名优化:启用短域名,例如:m.abc.com,便于用户记忆,方便搜索蜘蛛查找,减 ...
- springMVC 缓存(入门 spring+mybaties+redis一)
使用redis之前需要咋电脑上安装redis: 使用spring+mybaties+redis的本质是扩展类 org.apache.ibatis.cache.Cache:在我们自己扩展的Cache ...