uva 12003 分块

 大白上的原题，我就练练手。。。

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N = 3e5 + ;
const int SIZE = ;
ll block[N / SIZE + ][SIZE + ];
ll A[N];

int query(int L, int R, int v)
{
    int k = ;
    int lb = L / SIZE, rb = R / SIZE;
    if(lb == rb) { for(int i = L; i <= R; ++i) if(A[i] < v) k++; }
    else {
            for(int i = L; i < (lb + ) * SIZE; ++i) if(A[i] < v) k++;
            for(int i = rb * SIZE; i <= R; ++i) if(A[i] < v) k++;
            for(int i = lb + ; i < rb; ++i) {
                k += lower_bound(block[i], block[i] + SIZE, v) - block[i];
            }
    }
    return k;
}
void change(int k, int u, int p, int L, int R)
{
    ll x = (ll)u * k / (R - L + );
    if(A[p] == x) return;

    int la = p / SIZE;
    ll* B = &block[la][];
    int pos = ;
    ll old = A[p];
    while(B[pos] < old) pos++;
    A[p] = x; B[pos] = x;
    if(x > old) {
        while(pos < SIZE -  && B[pos] > B[pos + ]) { swap(B[pos + ], B[pos]); pos++; }
    }
    else {
        while(pos >  && B[pos] < B[pos - ]) { swap(B[pos - ], B[pos]); pos--; }
    }
}
int main()
{
    int n, m, u;
    while(~scanf("%d%d%d", &n, &m, &u))
    {
        int j = , k = ;
        for(int i = ; i < n; ++i)
        {
            scanf("%lld", &A[i]);
            block[k][j++] = A[i];
            if(j == SIZE) { k++; j = ; }
        }
        for(int i = ; i < k; ++i) sort(block[i], block[i] + SIZE);
        if(j) sort(block[k], block[k] + j);
        int L, R, v, p;
        while(m --)
        {
            int ans = ;
            scanf("%d%d%d%d", &L, &R, &v, &p);
            L--; R--; p--;
            ans = query(L, R, v);
            change(ans, u, p, L, R);
        }
        for(int i = ; i < n; ++i) printf("%lld\n", A[i]);
    }
    return ;
}