Oil Deposits

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 7955    Accepted Submission(s): 4678

Problem Description
The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous square plots. It then analyzes each plot separately, using sensing equipment to determine whether or not the plot contains oil. A plot containing oil is called a pocket. If two pockets are adjacent, then they are part of the same oil deposit. Oil deposits can be quite large and may contain numerous pockets. Your job is to determine how many different oil deposits are contained in a grid.

 
Input
The input file contains one or more grids. Each grid begins with a line containing m and n, the number of rows and columns in the grid, separated by a single space. If m = 0 it signals the end of the input; otherwise 1 <= m <= 100 and 1 <= n <= 100. Following this are m lines of n characters each (not counting the end-of-line characters). Each character corresponds to one plot, and is either `*', representing the absence of oil, or `@', representing an oil pocket.

 
Output
For each grid, output the number of distinct oil deposits. Two different pockets are part of the same oil deposit if they are adjacent horizontally, vertically, or diagonally. An oil deposit will not contain more than 100 pockets.

 
Sample Input
1 1
*
3 5
*@*@*
**@**
*@*@*
1 8
@@****@*
5 5
****@
*@@*@
*@**@
@@@*@
@@**@
0 0
 
Sample Output
0
1
2
2

;
}

小学生玩ACM----广搜的更多相关文章

  1. HDU 5652(二分+广搜)

    题目链接:http://acm.hust.edu.cn/vjudge/contest/128683#problem/E 题目大意:给定一只含有0和1的地图,0代表可以走的格子,1代表不能走的格 子.之 ...

  2. nyoj 613 免费馅饼 广搜

    免费馅饼 时间限制:1000 ms  |  内存限制:65535 KB 难度:3   描述 都说天上不会掉馅饼,但有一天gameboy正走在回家的小径上,忽然天上掉下大把大把的馅饼.说来gameboy ...

  3. UVa12726 one Friend at a Time (位 广搜)

    题目链接:UVa12726 是个PDF,不好复制进来. 大意:有个人要追个妹子,想加妹子QQ,但是不知道谁规定的,玩QQ的人要加好友必须先要有至少k个共同好友.共有N个人玩QQ,编号为1到N,1是男主 ...

  4. nyoj 592 spiral grid(广搜)

    题目链接:http://acm.nyist.net/JudgeOnline/problem.php?pid=592 解决以下问题后就方便用广搜解: 1.将数字坐标化,10000坐标为(0,0),这样就 ...

  5. nyoj 523 双向广搜

    题目链接: http://acm.nyist.net/JudgeOnline/problem.php?pid=523 #include<iostream> #include<cstd ...

  6. (广搜)Fire Game -- FZU -- 2150

    http://acm.hust.edu.cn/vjudge/contest/view.action?cid=82828#problem/I Fire Game Time Limit:1000MS    ...

  7. 中南大学oj:1336: Interesting Calculator(广搜经典题目)

    http://acm.csu.edu.cn/OnlineJudge/problem.php?id=1336 There is an interesting calculator. It has 3 r ...

  8. BFS广搜题目(转载)

    BFS广搜题目有时间一个个做下来 2009-12-29 15:09 1574人阅读 评论(1) 收藏 举报 图形graphc优化存储游戏 有时间要去做做这些题目,所以从他人空间copy过来了,谢谢那位 ...

  9. TZOJ 5279 马拉松比赛(广搜)

    描述 有一块矩形的海域,其中有陆地也有海洋,这块海域是CSUFT_ACM集训队的训练基地,这一天,昌神说要集训队的队员不能总是训练,于是昌神提出了中南林ACM集训队第一场环陆马拉松比赛,顾名思义就是围 ...

  10. hrbust 1621 迷宫问题II 广搜

    题目链接:http://acm.hrbust.edu.cn/vj/index.php?/vj/index.php?c=&c=contest-contest&cid=134#proble ...

随机推荐

  1. vs2013编译boost库

    打开vs2013>>visual studio tools>>VS2013 x64 本机工具命令提示 cd D:\lib\boost_1_55_0\boost_1_55_0 b ...

  2. [反汇编练习] 160个CrackMe之020

    [反汇编练习] 160个CrackMe之020. 本系列文章的目的是从一个没有任何经验的新手的角度(其实就是我自己),一步步尝试将160个CrackMe全部破解,如果可以,通过任何方式写出一个类似于注 ...

  3. 最简单的视音频播放示例7:SDL2播放RGB/YUV

    本文记录SDL播放视频的技术.在这里使用的版本是SDL2.实际上SDL本身并不提供视音频播放的功能,它只是封装了视音频播放的底层API.在Windows平台下,SDL封装了Direct3D这类的API ...

  4. jsp防盗链代码

    // 禁止缓存   response.setHeader("Cache-Control", "no-store");   response.setHeader( ...

  5. Most Powerful(ZOJ 3471状压dp)

    题意:n个原子,两两相撞其中一个消失,产生能量,给出任意两原子相撞能产生的能量,求能产生的最大能量. 分析:dp[i]表示情况为i时产生的最大能量 /*#include <map> #in ...

  6. codeforces 260 div2 B题

    打表发现规律,对4取模为0的结果为4,否则为0,因此只需要判断输入的数据是不是被4整出即可,数据最大可能是100000位的整数,判断能否被4整出不能直接去判断,只需要判断最后两位(如果有)或一位能否被 ...

  7. selenium打开带有扩展的chrome

    每当用跑用例失败的时候,第一反应就是查看元素定位是不是正确,帮助定位的扩展是必不可少的,但是selenium一般打开的是不带扩展的干净的浏览器,如果操作步骤很长的话,就得手动去执行直到那一步去检查元素 ...

  8. ASP.NET常用技巧方法代码断

    1. 打开新的窗口并传送参数:传送参数:response.write("<script>window.open('*.aspx?id="+this.DropDownLi ...

  9. lighttpd为什么要accept多次呢

    在lighttpd网络模型里面我们可以看到以下代码 /* accept()s at most 100 connections directly * * we jump out after 100 to ...

  10. CentOS6.2编译安装codelite5.3

    这两天实验室要求在服务器上安装一个codelite,于是由我对服务器下手,上网看了下悲剧的发现codelite不支持在centos上直接安装,只能编译安装,经过一番折腾之后,成功的装上了,下面是我的安 ...