Reverse Words in a String II
Given an input string, reverse the string word by word. A word is defined as a sequence of non-space characters.
The input string does not contain leading or trailing spaces and the words are always separated by a single space.
For example,
Given s = "the sky is blue",
return "blue is sky the".
Could you do it in-place without allocating extra space?
先把每个词反转一遍, 再把整个string 反转一遍。
public class Solution {
public void reverseWords(char[] s) {
for(int i = 0, j = 0; j <= s.length && i < s.length; j ++){
if(j == s.length || s[j] == ' '){
reverse(s, i, j - 1);
i = j + 1;
}
}
reverse(s, 0, s.length - 1);
}
private void reverse(char[] c, int s, int e){
while(s < e){
char tmp = c[s];
c[s] = c[e];
c[e] = tmp;
s ++; e --;
}
}
}
Reverse Words in a String II的更多相关文章
- Reverse Words in a String I & Reverse Words in a String II
Reverse Words in a String I Given an input string, reverse the string word by word. For example,Give ...
- [LeetCode] Reverse Words in a String II 翻转字符串中的单词之二
Given an input string, reverse the string word by word. A word is defined as a sequence of non-space ...
- LeetCode Reverse Words in a String II
原题链接在这里:https://leetcode.com/problems/reverse-words-in-a-string-ii/ 题目: Given an input string, rever ...
- [Swift]LeetCode186. 翻转字符串中的单词 II $ Reverse Words in a String II
Given an input string, reverse the string word by word. A word is defined as a sequence of non-space ...
- [LeetCode] 186. Reverse Words in a String II 翻转字符串中的单词 II
Given an input string, reverse the string word by word. A word is defined as a sequence of non-space ...
- 186. Reverse Words in a String II
题目: Given an input string, reverse the string word by word. A word is defined as a sequence of non-s ...
- leetcode 186. Reverse Words in a String II 旋转字符数组 ---------- java
Given an input string, reverse the string word by word. A word is defined as a sequence of non-space ...
- Leetcode - 186 Reverse Words in a String II
题目: Given an input string, reverse the string word by word. A word is defined as a sequence of non-s ...
- 186. Reverse Words in a String II 翻转有空格的单词串 里面不变
[抄题]: Given an input string , reverse the string word by word. Example: Input: ["t"," ...
随机推荐
- CF1111E Tree 树链剖分,DP
CF1111E Tree 过年了,洛咕还没爬这次的题,先放个CF的链接吧. 补个LG传送门. 对于每个询问点\(x\),设它的祖先即不能和它放在同一个集合中的点的个数为\(f[x]\),设\(dp[i ...
- CS100.1x-lab1_word_count_student
这是CS100.1x第一个提交的有意义的作业,自己一遍做下来对PySpark的基本应用应该是可以掌握的.相关ipynb文件见我github. 这次作业的目的如题目一样--word count,作业分成 ...
- pycharm导入路径问题
博主在导入自定义模块式出现模块下有红色波浪线,如下: 例如from conf import setting 导入时会从当前目录下找找到youkuClient就不会再往下找了,所以引入模块的路径不能夸路 ...
- 【TestNG测试】TestNG、Maven、testng.xml构建测试工程
创建一个maven工程 使用Idea创建maven工程 建立类似如上的工程结构,src/main/java,src/test/java,pom.xml,testng.xml,这里由于我们使用工程是 ...
- 【LeetCode算法题库】Day7:Remove Nth Node From End of List & Valid Parentheses & Merge Two Lists
[Q19] Given a linked list, remove the n-th node from the end of list and return its head. Example: G ...
- 剑指offer试题(PHP篇三)
21.栈的压入.弹出序列 题目描述 输入两个整数序列,第一个序列表示栈的压入顺序,请判断第二个序列是否为该栈的弹出顺序.假设压入栈的所有数字均不相等.例如序列1,2,3,4,5是某栈的压入顺序,序列4 ...
- Windows下用HackRF和SDR#收听FM
本文内容.开发板及配件仅限用于学校或科研院所开展科研实验! 淘宝店铺名称:开源SDR实验室 HackRF链接:https://item.taobao.com/item.htm?spm=a1z10.1- ...
- 虚拟机中安装MAC OS X教程(适用所有电脑方法,特别是cpu不支持硬件虚拟化的电脑)
前言 之前写了一篇在Windows上搭建Object-C开发环境,并且写了一个HelloWorld程序.但真正开发苹果软件是在MAC OS X系统中(以下简称OSX)中.买不起MacBook,也没有O ...
- 分布式消息队列RocketMQ与Kafka架构上的巨大差异
分布式消息服务 Kafka 是一个高吞吐.高可用的消息中间件服务,适用于构建实时数据管道.流式数据处理.第三方解耦.流量削峰去谷等场景,具有大规模.高可靠.高并发访问.可扩展且完全托管的特点,是分布式 ...
- 【文章存档】Azure Web 应用如何修改 IIS 配置
链接 https://docs.azure.cn/zh-cn/articles/azure-operations-guide/app-service-web/aog-app-service-web-h ...