简单题。

#include<iostream>
#include<cstring>
#include<cmath>
#include<algorithm>
#include<cstdio>
#include<map>
#include<queue>
#include<vector>
using namespace std; int n;
struct X
{
string a;
string b;
bool flag;
} s[+]; int main()
{
scanf("%d",&n);int fail=;
for(int i=; i<=n; i++)
{
cin>>s[i].a>>s[i].b;
s[i].flag=; for(int j=; j<s[i].b.length(); j++)
{
if(s[i].b[j]=='') s[i].flag=,s[i].b[j]='@';
if(s[i].b[j]=='') s[i].flag=,s[i].b[j]='%';
if(s[i].b[j]=='l') s[i].flag=,s[i].b[j]='L';
if(s[i].b[j]=='O') s[i].flag=,s[i].b[j]='o'; }
fail=fail+s[i].flag;
}
if(fail==)
{
if(n==||n==) printf("There is %d account and no account is modified\n",n);
else printf("There are %d accounts and no account is modified\n",n);
}
else
{
printf("%d\n",fail);
for(int i=; i<=n; i++)
{
if(s[i].flag==) continue;
cout<<s[i].a<<" "<<s[i].b<<endl;
}
}
return ;
}

PAT (Advanced Level) 1035. Password (20)的更多相关文章

  1. PTA (Advanced Level)1035.Password

    To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem ...

  2. PAT (Advanced Level) 1077. Kuchiguse (20)

    最长公共后缀.暴力. #include<cstdio> #include<cstring> #include<cmath> #include<vector&g ...

  3. PAT (Advanced Level) 1061. Dating (20)

    简单模拟. #include<stdio.h> #include<string.h> ],s2[],s3[],s4[]; ][]={"MON ", &quo ...

  4. PAT (Advanced Level) 1008. Elevator (20)

    简单模拟. 注意a[i]==a[i-1]的情况. #include<iostream> #include<cstring> #include<cmath> #inc ...

  5. 【PAT甲级】1035 Password (20 分)

    题意: 输入一个正整数N(<=1000),接着输入N行数据,每行包括一个ID和一个密码,长度不超过10的字符串,如果有歧义字符就将其修改.输出修改过多少组密码并按输入顺序输出ID和修改后的密码, ...

  6. PAT (Advanced Level) Practice 1035 Password (20 分) 凌宸1642

    PAT (Advanced Level) Practice 1035 Password (20 分) 凌宸1642 题目描述: To prepare for PAT, the judge someti ...

  7. PAT 甲级 1035 Password (20 分)(简单题)

    1035 Password (20 分)   To prepare for PAT, the judge sometimes has to generate random passwords for ...

  8. PAT (Advanced Level) Practice 1046 Shortest Distance (20 分) 凌宸1642

    PAT (Advanced Level) Practice 1046 Shortest Distance (20 分) 凌宸1642 题目描述: The task is really simple: ...

  9. PAT (Advanced Level) Practice 1042 Shuffling Machine (20 分) 凌宸1642

    PAT (Advanced Level) Practice 1042 Shuffling Machine (20 分) 凌宸1642 题目描述: Shuffling is a procedure us ...

随机推荐

  1. PHP实现远程图片下载

    /** * 文件下载 * @param string $url */ public function download() { $url = $this->input->get_post( ...

  2. 使用ABAP正则表达式解析HTML标签

    需求就是我用ABAP的某个函数从数据库读取一个字符串出来,该字符串的内容是一个网页. 网页的form里包含了很多隐藏的input field.我的任务是解析出name为svyValueGuid的inp ...

  3. Unity3D 在自定义脚本中实现Button组件上的OnClick面板

    下述内容不对c#语法做过多讲解,仅对已入门并有兴趣的同学做为学习和拓展的资料 大家在Unity制作的过程中一定都使用过UI功能,那么很多人也一定见过这个面板: 那么我们如何能在自己的脚本中添加上像On ...

  4. powerDesigner 一些设置

    常用设置 table中需要显示的内容 --------------------------------------------------------------------------------- ...

  5. Linux之用户权限管理

    chmod(更改目录或文件权限) 在linux中,文件的权限分为3中,拥有者,群组,其他人.而chmod则是对权限更改的命令. u 表示该文件的拥有者,g 表示与该文件的拥有者属于同一个组,o 表示其 ...

  6. 写的一个HttpClient类

    package com.ca.test.cainterface.common.util.http; import com.ca.test.cainterface.common.util.data.Da ...

  7. mkdir touch vim

    vim和touch都用于新建文件 mkdir用于新建文件夹

  8. IntelliJ IDEA集成工具Database连接MySQL8.0报错的解决方法

    直接用默认配置连接的话,会报以下错误: Connection to MySQL - @localhost failed. [08001] Could not create connection to ...

  9. 出现了错误。详细消息: 3 uncommitted changes would be overwritten by merge

    merge manual中有一条警告: 出现了错误.详细消息: 3 uncommitted changes would be overwritten by merge 有未提交修改情况下,不要执行me ...

  10. for、while循环

    for循环 # for 循环后面可以对Iterable或者Iterator进行遍历 # "abc"和[1,2,3]为可迭代对象,range(4)为迭代器 for i in &quo ...