Codeforces Round #459 (Div. 2)-A. Eleven

A. Eleven

time limit per test1 second

memory limit per test256 megabytes

Problem Description

Eleven wants to choose a new name for herself. As a bunch of geeks, her friends suggested an algorithm to choose a name for her. Eleven wants her name to have exactly n characters.

Her friend suggested that her name should only consist of uppercase and lowercase letters ‘O’. More precisely, they suggested that the i-th letter of her name should be ‘O’ (uppercase) if i is a member of Fibonacci sequence, and ‘o’ (lowercase) otherwise. The letters in the name are numbered from 1 to n. Fibonacci sequence is the sequence f where

f1 = 1,

f2 = 1,

fn = fn - 2 + fn - 1 (n > 2).

As her friends are too young to know what Fibonacci sequence is, they asked you to help Eleven determine her new name.

Input

The first and only line of input contains an integer n (1 ≤ n ≤ 1000).

Output

Print Eleven’s new name on the first and only line of output.

Examples

input

8

output

OOOoOooO

input

15

output

OOOoOooOooooOoo

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解题心得：

1. 就是考的一个斐波那契的问题，很简单。

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#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
const int maxn = 1e5+100;
int num[maxn];
bool vis[maxn];
int main()
{
   memset(num,0,sizeof(num));
   memset(vis,0,sizeof(vis));
   num[0] = 1,num[1] = 1;
   int n;
   scanf("%d",&n);
   for(int i=2;;i++)
   {
       num[i] = num[i-1] + num[i-2];
       vis[num[i]] = true;
       if(num[i] > 3000)
            break;
   }
   vis[1] = true;
   for(int i=1;i<=n;i++)
        if(vis[i])
            printf("O");
        else
            printf("o");
    return 0;
}